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natali 33 [55]
1 year ago
12

Cheating: According to a report on academic cheating by ETS, the Educational Testing Service, college students majoring in Busin

ess and Engineering are more likely to cheat than students in other majors. For a statistics project, a community college student at Diablo Valley College (DVC) decides to investigate cheating in two popular majors at DVC: business and nursing. She convinces professors who teach business and nursing courses to distribute a short anonymous survey in their classes. The question about cheating is one of many other questions about college life. From this data, the student plans to calculate a confidence interval for the difference in two population proportions. Which is the most reasonable description of the two populations for her conclusion? business and nursing students in the classes that were surveyed business and nursing students at DVC business and nursing students at community colleges business and nursing students at community colleges the year of the study
Mathematics
1 answer:
miss Akunina [59]1 year ago
5 0

The most reasonable description of the two populations for her conclusion   is business and nursing students in the classes that were surveyed at  Diablo Valley College (DVC).

Step-by-step explanation:

The question itself indicates that., For a statistics project, a community college student at Diablo Valley College (DVC) decides to investigate cheating in two popular majors at DVC in order to find out the most academic cheaters.,

also the researcher( student) convinces the professors who teach business and nursing courses at DVC to distribute a short anonymous survey in their classes. So., The most reasonable description of the two populations for her conclusion is business and nursing students in the classes that were surveyed at  Diablo Valley College (DVC).

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Zanzabum
317 is the answer you are looking for.
6 0
1 year ago
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Ms. Lindsey surveyed a random sample of students at her school to determine how they got to school. The results are shown below:
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20 I think because 8+12
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The number of airline passengers in 1990 was 466 million. The number of passengers traveling by airplane each year has increased
taurus [48]

Answer:

2010.

Step-by-step explanation:

We have been given an exponential growth formula P(t)=466\cdot 1.035^t, which represents number of passengers traveling by airplane since 1990.

To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:

900=466\cdot 1.035^t

\frac{900}{466}=\frac{466\cdot 1.035^t}{466}1.9313304721030043=1.035^t

Take natural log of both sides:

\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)

Using property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)

0.658209129198=t\cdot 0.034401426717

\frac{0.658209129198}{0.034401426717}=\frac{t\cdot 0.034401426717}{0.034401426717}

19.1331927775=t\\\\t=19.1331927775

This means that in the 20th year since 1990, 900 million passengers would travel by airline.

1990+20=2010

Therefore, 900 million passengers would travel by airline in 2010.

6 0
1 year ago
A Deloitte employment survey asked a sample of human resource executives how their company planned to change its workforce over
marishachu [46]

Answer:

employment plan for the next 12 months is not independent of the type of company

Step-by-step explanation:

H0 : employment plan for the next 12 months is independent of the type of company

H1 : employment plan for the next 12 months is not independent of the type of company

The Chisquare statistic, χ² :

χ² = (observed - Expected)²/ Expected

Given the data:

Observed values :

_________________ Company

Emp plan ________ private _____ public _total

Add employees _____ 37 ________ 32 __ 69

No change__________19 ________ 34 __53

Layoff employees ____ 16 ________ 42__58

Total ______________72 ________108 _ 180

The expected value counts :

(Row total * column total) / grand total

Expected Values:

27.6 ___41.4

21.2 ___ 31.8

23.2 ___34.8

Chi-Squared Values:

3.20145 ___2.1343

0.228302__ 0.152201

2.23448 ____1.48965

χ² = (3.20145 + 2.1343 + 0.228302 + 0.152201 + 2.23448 + 1.48965)

χ² = 9.440383

Degree of freedom, df (row - 1) * (column - 1) = (3-1) * (2 - 1) = 2 * 1 = 2

Pvalue from Chisquare statistic, df = 2

Pvalue = 0.008913

Since ;

Pvalue < α ; We reject the null and conclude that employment plan for the next 12 months is not independent of the type of company.

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Not sure about the first part but X is 11 because if 14 is congruent to x + 3 then you just do 14-3 which is 11 and then since you figured out x is 11 you just plug that into 11-y and so if it needs to equal 3 then 11-3 = 8. So basically x=11 y=8
3 0
1 year ago
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