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valina [46]
2 years ago
5

In the 2009-2010 school year in country A, there were 92,000 foreign students from country B. This number I 23% more than the nu

mber of students from country C. How many foreign students were from country C?
Mathematics
1 answer:
max2010maxim [7]2 years ago
8 0

Answer:

\approx74796

Step-by-step explanation:

GIVEN: In the 2009-10 school year in country A, there were 92,000 foreign students from country B. This number is 23\% more than the number of students from country C.

TO FIND: How many foreign students were from country C.

SOLUTION:

Total foreign students from country B =92000

let the foreign students from country C be x

As the students from country B is 23\% more than the country C

Students from country B

92000=\frac{123}{100}x

x=\frac{9200000}{123}

x\approx74796

Hence the number of students from country C are 74796

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To find the distance between (-2,-3) and (4,1), Peggy's teacher drew a diagram and marked blue lines to represent the legs of a
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Answer:

Ik this is late but the answer is A

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2 years ago
1.How much taller Porter is than Henry, given that Porter is n inches tall and Henry is m inches tall. 2.How many times as tall
EleoNora [17]

Answer:

Porter is n-m inches taller than Henry.

Porter is \frac{n}{m} times taller than henry.

Step-by-step explanation:

The difference in height can be found using subtraction.

Since Porter is taller than Henry, we'll subtract away Henry's height from Porter's height. This will leave us with only the difference between the heights.

n = Porter's height

m = Henry's height

Difference in height is thus:

n-m

Answer: Porter is n-m inches taller than Henry.

To find out how many times taller Porter is than Henry, we can use division.

An example: if Porter was 200cm, and Henry was 100cm, Porter is obviously 2 times as tall.

If we divide Porter's height by Henry's height...

\frac{200}{100}=2

..we'll get 2. This is because Henry's height "fits in twice" in Porter's height. 100 fits twice in 200.

Using our values, n and m, we'll divide n by m.

\frac{n}{m}

Answer: Porter is \frac{n}{m} times taller than henry.

3 0
2 years ago
Find the value of x RT=4x+10 SW= 5x-20
Liula [17]
Well, as you can see from the rectangle RT and SW should have equal lengths. So to find the value of x, we need to do.....

4x + 10 = 5x - 20
-x + 10 = -20              (Subtraction property of equality)
-x = -30                      (Subtraction property of equality)
x = 30                        (Division property of equality)

To check our work:

4(30)+10 = 130
5(30)-20 = 130

So, the value of x is 30!


5 0
2 years ago
Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi
s2008m [1.1K]

Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

7 0
2 years ago
What is the greatest common factor of x2y and xy2 ?
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GCF of :2xy and 2xy
   

2(x+y)

5 0
2 years ago
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