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7nadin3 [17]
2 years ago
6

At what celsius temperature does 0.750mol of an ideal gas occupy a volume of 35.9L at 114kPa

Chemistry
1 answer:
pashok25 [27]2 years ago
8 0

Answer:

378.25°C

Explanation:

Given data:

Number of moles of gas = 0.750 mol

Volume of gas = 35.9 L

Pressure of gas = 114 KPa (114/101 = 1.125 atm)

Temperature of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

now we will put the values.

T = PV/nR

T = 1.125 atm × 35.9 L /0.750 mol  × 0.0821 atm.L/ mol.K

T = 40.3875/0.062/K

T = 651.4 K

Kelvin to °C:

651.4 K - 273.15 = 378.25°C

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Eva8 [605]

Answer:

Since with LiBr no precipitation takes place. So, Ag+ is absent

When we add Li2SO4 to it, precipitation takes place.

Ca2+(aq) + SO42-(aq) ----> CaSO4(s) ...Precipitate

Thus, Ca2+ is present.

When Li3PO4 is added, again precipitation takes place.Reaction is:

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8 0
2 years ago
Why does 5060 have three significant figures?
Morgarella [4.7K]
<h2>5060 have three significant figures : Explanation given below </h2>

Explanation:

Significant figures

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It  includes all digits except: zeros

Rules to find significant figures

1.All non-zero digits are considered significant. For example, 23  has two significant figures.

2.Zeros in between two non-zero digits are significant: like in 202.1201  has seven significant figures.

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That is the reason in number 5060 , it has 3 significant figures .

3 0
2 years ago
How many capsules containing 75mg of Tamiflu could be produced from 155g of star anise.?
jeyben [28]
From the question you will find that:
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1 capsule   = 2.6 g tamiflu
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7 0
2 years ago
The concentration of Si in an Fe-Si alloy is 0.25 wt%. What is the concentration in kilograms of Si per cubic meter of alloy?
kodGreya [7K]

Answer : The concentration of Si in kilograms is, 19.55kg/m^3

Explanation :

As we are given that, the concentration of Si in an Fe-Si alloy is 0.25 wt% that means:

Weight of Si = 0.25 g = 0.00025 kg

Weight of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg

Density of Si = 2.32g/cm^3=2.32\times 10^6g/m^3

Density of Fe = 7.87g/cm^3=7.87\times 10^6g/m^3

Now we have to calculate the concentration in kilograms of Si per cubic meter of alloy.

Concentration of Si in kilograms =  \frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}

Concentration of Si in kilograms =  \frac{\text{Weight of Si in 100 g of alloy}}{\frac{\text{Wight of Fe}}{\text{Density of Fe}}+\frac{\text{Wight of Si}}{\text{Density of Si}}}

Now put all the given values in this expression, we get:

Concentration of Si in kilograms = \frac{0.00025kg}{\frac{99.75g}{7.87\times 10^6g/m^3}+\frac{0.25g}{2.23\times 10^6g/m^3}}

Concentration of Si in kilograms = 19.55kg/m^3

Thus, the concentration of Si in kilograms is, 19.55kg/m^3

5 0
2 years ago
A 17.0-g sample of hf is dissolved in water to give 2.0 x 10 2 ml of solution. the concentration of the solution is:
fredd [130]
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 Explanation

molarity=moles/volume in liters

moles  = mass/molar mass
molar mass  of HF = 19 + 1 =  20 g/mol
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volume in  liters = 2  x10^2ml/1000 = 0.2  liters

therefore  molarity =  0.85/0.2 = 4.25  M
8 0
2 years ago
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