Imagine that you wanted to utilize a voltage divider to provide an RMS AC output voltage of 10V using a typical 120V (RMS) US ho
usehold wall socket as the input. For this situation write down a simple mathematical relationship relating the resistance values of the two resistors R1 and R2 that you would use in your circuit.
1 answer:
You might be interested in
Answer:
Vx = 6.242 x 10raised to power 15
Vy = -6.242 x 10raised to power 15
Explanation:
from E = IVt
but V = IR from ohm's law and Q = It from faraday's first law
I = Q/t
E = Q/t x V x t = QV
hence, E =QV
V = E/Q
Answer:
a)σ₁ = 265.2 MPa
b)σ₂ = -172.8 MPa
c)
d)Range = 438 MPa
Explanation:
Given that
Mean stress ,σm= 46.2 MPa
Stress amplitude ,σa= 219 MPa
Lets take
Maximum stress level = σ₁
Minimum stress level =σ₂
The mean stress given as
2 x 46.2 = σ₁ + σ₂
σ₁ + σ₂ = 92.4 MPa --------1
The amplitude stress given as
2 x 219 = σ₁ - σ₂
σ₁ - σ₂ = 438 MPa --------2
By adding the above equation
2 σ₁ = 530.4
σ₁ = 265.2 MPa
-σ₂ = 438 -265.2 MPa
σ₂ = -172.8 MPa
Stress ratio
Range = 265.2 MPa - ( -172.8 MPa)
Range = 438 MPa