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adell [148]
2 years ago
7

After a storm damage is the community center she gotten her friend told fundraising events out pay for repairs after the first e

vent they raise $240 with the temperature in the total amount that they want to raise rAfter a storm damage is the community center can you get a new friend told fundraising event shall pay for repairs after the first event they raise $240 with a temperature of the Tylenol that they want to raise what is what amount of money that she got her friend want to raise
Mathematics
1 answer:
brilliants [131]2 years ago
8 0

Question:

After a storm damages the community center, Shanika and her friends hold fundraising events to help pay for repairs. After the first event, they raise $240, which is 10% of the total amount that they want to raise. What is the total amount of money that Shanika and her friends want to raise?

Answer:

The total amount of money that Shanika and her friends want to raise is $2400

Step-by-step explanation:

Here we have the amount raised = $240

Also we are told that the amount raised is only 10% of the amount they want to raise

Therefore if we put the amount they want to raise as D we have

10% of D = $240

That is;

\frac{10}{100} \times D = \$240

That means

D = \$240 \times  \frac{100}{10}  = 10 \times  \$240 = \$2400

Therefore, the total amount of money that Shanika and her friends want to raise = $2400.

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Juli2301 [7.4K]

Answer:

<em>0.85 Euros have the same amount as 1 U.S dollar.</em>

Step-by-step explanation:

The given equation is:   E= \frac{17}{20}D , where E= amount of Euros and D= amount of U.S dollar.

Now for 1 U.S dollar, we need to plug D= 1 into the above equation. So, we will get.........

E= \frac{17}{20}(1) \\ \\ E= \frac{17}{20}= 0.85

Thus, 0.85 Euros have the same amount as 1 U.S dollar.

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Solve the system of equations given by 5x – 2y = -6 and 15x – 6y = 6
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In the diagram, AC=BD=17 and BC=3. The length of segment AD is
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A process manufactures ball bearings with diameters that are normally distributed with mean 25.1 mm and standard deviation 0.08
marta [7]

Answer:

(a) The proportion of the diameters are less than 25.0 mm is 0.1056.

(b) The 10th percentile of the diameters is 24.99 mm.

(c) The ball bearing that has a diameter of 25.2 mm is at the 84th percentile.

(d) The proportion of the ball bearings meeting the specification is 0.8881.

Step-by-step explanation:

Let <em>X</em> = diameters of ball bearings.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 25.1 mm and standard deviation, <em>σ</em> = 0.08 mm.

To compute the probability of a Normally distributed random variable we need to first convert the raw scores to <em>z</em>-scores as follows:

<em>z</em> = (X - μ) ÷ σ

(a)

Compute the probability of <em>X</em> < 25.0 mm as follows:

P (X < 25.0) = P ((X - μ)/σ < (25.0-25.1)/0.08)

                    = P (Z < -1.25)

                    = 1 - P (Z < 1.25)

                    = 1 - 0.8944

                    = 0.1056

*Use a <em>z</em>-table for the probability.

Thus, the proportion of the diameters are less than 25.0 mm is 0.1056.

(b)

The 10th percentile implies that, P (X < x) = 0.10.

Compute the 10th percentile of the diameters as follows:

P (X < x) = 0.10

P ((X - μ)/σ < (x-25.1)/0.08) = 0.10

P (Z < z) = 0.10

<em>z</em> = -1.282

The value of <em>x</em> is:

z = (x - 25.1)/0.08

-1.282 = (x - 25.1)/0.08

x = 25.1 - (1.282 × 0.08)

  = 24.99744

  ≈ 24.99

Thus, the 10th percentile of the diameters is 24.99 mm.

(c)

Compute the value of P (X < 25.2) as follows:

P (X < 25.2) = P ((X - μ)/σ < (25.2-25.1)/0.08)

                    = P (Z < 1.25)

                    = 0.8944

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*Use a <em>z</em>-table for the probability.

Thus, the ball bearing that has a diameter of 25.2 mm is at the 84th percentile.

(d)

Compute the value of P (25.0 < X < 25.3) as follows:

P (25.0 < X < 25.3) = P ((25.0-25.1)/0.08 < (X - μ)/σ < (25.3-25.1)/0.08)

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*Use a <em>z</em>-table for the probability.

Thus, the proportion of the ball bearings meeting the specification is 0.8881.

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