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Marina86 [1]
2 years ago
5

A Statistics class is estimating the mean height of all female students at their college. They collect a random sample of 36 fem

ale students and measure their heights. The mean of the sample is 65.3 inches. The standard deviation is 5.2 inches. Use the T-distribution Inverse Calculator applet to answer the following question. What is the 90% confidence interval for the mean height of all female students in their school?
a. (56.5, 74.1)
b. (63.6, 67.0)
c. (63.8, 66.8)
d. (63.9, 66.7)
Mathematics
1 answer:
Galina-37 [17]2 years ago
4 0

Answer:

d. ( 63.9, 66.7)

Therefore at 90% confidence interval (a,b) = ( 63.9, 66.7)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 65.3

Standard deviation r = 5.2

Number of samples n = 36

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

65.3+/-1.645(5.2/√36)

65.3+/-1.645(0.866667)

65.3+/-1.42567

65.3+/-1.4

= ( 63.9, 66.7)

Therefore at 90% confidence interval (a,b) = ( 63.9, 66.7)

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<u>b</u>

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It can be calculated as:

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The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

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