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2 years ago

If ABCD is a parallelogram, which of the following statements must be true?

Mathematics

2 answers:

hoa [83]2 years ago

8 0

Answer: d. AB = CD and BC = AD

Step-by-step explanation:

We know that parallelogram is a quadrilateral with properties listed below:-

The opposite sides are congruent ( AB = CD and BC = AD ).
The opposite angels are congruent (∠A=∠C and ∠D=∠B).
The consecutive angles are supplementary (∠A + ∠D = 180°).
The diagonals of a parallelogram bisect each other.
If one angle is right, then all angles are right.

7nadin3 [17]2 years ago

3 0

D the opposing sides are equal but parallel

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. Cara is playing a game. For each dart she can toss onto a board, she

Kaylis [27]

She will need 12 seconds because -20•12=-240

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1 year ago

A deer population is estimated to be 4,350. The growth rate of the population is given by the equation y=4350(1.07) . What is th

HACTEHA [7]

Answer:

Step-by-step explanation:

Analyzing the growth rate of 1.07:

If the growth rate is a number greater than 1, we have exponential growth; if the growth rate is a number greater than 0 but less than 1, we have exponential decay.

Our growth rate is actually growth. But the rate of growth is not 107%. The rate of growth means that we already had 100% of the population and that it is growing by 7% each year. 100% + 7% = 107%; as a decimal, 1.07

So the rate of growth is 7%

8 0

1 year ago

Write an expression that can be used to multiply 6 times 198 mentally

lara31 [8.8K]

100×6

6×90

6×8

add them together

community property

4 0

1 year ago

kabir spends 1/3of his pocket money on books,1/5on traveling and rest on food.if his pocket money is 450 rupees how much money d

Talja [164]

Answer:

210

Step-by-step explanation:

450 X 1/3 = 150

450 X 1/5 = 90

90 + 150 = 240

450 - 240 = 210

4 0

2 years ago

Let P be a point not on the line L that passes through the points Q and R. The distance d from the point P to the line L is d =

Goshia [24]

Answer:

Distance from point (0,1,1) to the given line is zero.

Step-by-step explanation:

Given parametric equations of line,

x=2t, y=5-2t, z=1+t

To find distance from (0,1,1), we have to eliminate t from above equations so that,

$y=5-2t=5-x\implies x+y=5=4+1=4+z-t=4+z-\frac{1}{2}x$

$\implies 3x+2y-2z-8=0\hfill (1)$

whose direction ratioes are (l,m,n)=(3,2,-2) and distance fro point (a,b,c)=(0,1,1) is given by,

$\frac{al+bm+cn}{\sqrt{l62+m^2+n^2}}=\frac{(3\times 0)+(2\times 1)+(-2)(1)}{\sqrt{3^2+2^2+(-2)^2}}=\frac{0+2-2}{\sqrt{17}}=0$

Distance between point (0,1,1) and (1) is zero. That is point 90,1,1) is lies on the line (1).

8 0

2 years ago