Answer:
I think is is a bit b
Step-by-step explanation:
a or b
Answer:
4 CUPS OF SUNFLOWER SEEDS for the larger batch
Step-by-step explanation:
From the small batch:
2 cups of peanuts= 1 cup of sunflower seeds
Since the ratios are thesame, it therefore means that the proportion will be thesame.
For the large batch:
8 cups of peanuts = X cups of sunflower seeds.
Mathematically, let's express it as:
Let p = cups of peanuts
S= cups of sunflower seeds
X = unknown number of sunflower seeds
Therefore, connecting equation is:
2P = 1S
8P = X's
Cross Multiply to solve for X
X's * 2P = 1S * 8P
2PX = 8P
X = 8P / 2P
It therefore means that there'll be a need of:
4 CUPS OF SUNFLOWER SEEDS for the larger batch
Answer:
The distance of flag post from Y is 38.13 m
Step-by-step explanation:
Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.
Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.
Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.
Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,



Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,



Refer attachment 1.
From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.
∠YFX+∠FYX+∠FXY=180°
∠YFX+50°+72°=180°
∠YFX=58°
Refer attachment 2.
Now the distance FY can be calculated using sin rule as follows,

Substituting the values,

Simplifying first two terms,
Cross multiplying,


m
The function is given by
y=45,200 + 1,900x
and is of the form y = mx+b , where m is the rate of change and b is the fixed value ( or we can say initial value)
Now when we compare we get m = 1,900 for our problem .
So the population increases every year by 1,900.
(3/4)∗π∗62=27π
Also , the goat can reach around the corners by 2 on the short sides and 1 on long side.creating 2 90 degree sectors of additional grazing area.(1/4)∗π∗22=π
(1/4)∗π∗12=π/4
27π+π+π/4=28.25π