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Bas_tet [7]
2 years ago
14

352L of chlorine under a pressure of 680. mm Hg are placed in a container under a pressure of 1210 mm Hg. The temperature remain

s constant at 296 K. What is the volume of the container in liters?​
Chemistry
1 answer:
Law Incorporation [45]2 years ago
8 0

Answer:

P1 = 680. mm P2 = 1210 mm

V1 = 352 mL V2 = ?

P1V1 = P2V2

V2 = P1V1/P2

V2 = 680. mm x 352 mL/1210 mm = 198 mL Cl2

Explanation:

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Answer:

Sample Response: Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s and the total momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.

Explanation:

Sample Response since i just took it on Edg.

5 0
2 years ago
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Combining aqueous solutions of bai2 and na2so4 affords a precipitate of baso4. Which ions are spectator ions in the reaction?
Marina86 [1]

Answer:

I⁻ (aq) and Na⁺ (aq)

Explanation:

We have the chemical reaction:

BaI₂ + Na₂SO₄ → BaSO₄ + 2 NaI

However if you want to determine the spectator ions you need  to write the states of compounds:

(aq) - ions dissolved in water

(s) - solid

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3 0
2 years ago
Two different compounds are obtained by combining nitrogen with oxygen. The first compound results from combining 46.7 gg of NN
mina [271]

Answer:

4.02

Explanation:

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So lets do our calculations:

First Compound:

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Second Compound:

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This result for all practical purposes is a whole number, and it is telling us that there are 4 times as many oxygen atoms in the second coumpound as in the first compound. This is so because the ratio we just calculated is also the ratio in mol atoms:

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and the molecular weights cancel each other.

The only N and O compounds that follow this ratio are N₂O₄ and N₂O, and this question could be made in a multiple choice to match  formulas.

3 0
2 years ago
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Elena L [17]
Let us differentiate accuracy from precision. Accuracy is the nearness of the measured value to the true or exact value. On the other hand, precision is the nearness of the measured values between each other. So, for precision, select the student in which the measured values are very near to each other. That would be Student III. Now, for accuracy, let's find the average for each student.

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2 years ago
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<span><span>
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<span><span>Hope this answers the question. Have a nice day.</span></span>

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2 years ago
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