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xxMikexx [17]
2 years ago
5

Angeline bought s yards of satin fabric priced at $8.09 per yard, and c yards of cotton fabric priced at $3.79 per yard. Use an

expression to determine the amount that Angeline would spend in all if she bought 5 yards of satin fabric and 8 yards of cotton fabric. *
Mathematics
2 answers:
telo118 [61]2 years ago
7 0

Answer:

$70.77

Step-by-step explanation:

A=8.09s+3.79c

A=8.09(5)+3.79(8)

A=40.45+30.32

A=70.77

Zinaida [17]2 years ago
6 0

Answer:

$70.77

Step-by-step explanation:

5s+8c=?

5(8.09) + 8(3.79) = ?

40.45 + 30.32 = ?

$70.77

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Suppose there are 500 units of energy available at the base of a pyramid of energy. How many units of that energy will the first
Ede4ka [16]

Answer:

With every other lever 10% of the energy with be transferred. In this case:  Primary Producers (500) 1) First- level consumer. (50)  2) Second-level consumer. (5) 3) Third- level consumer. (0.5) Remember the formula is:(Primary Producer) __units X 10%= __500 units X 10%= 50

50 units of energy will be the first level consumers stored.  

5 units of energy will be the second level consumers stored.

Step-by-step explanation:

3 0
2 years ago
What is the true solution to l n 20 + l n 5 = 2 l n x x = 5 x = 10 x = 50 x = 100
Pani-rosa [81]

Answer:

x = 10

Step-by-step explanation:

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Since logs of negative numebrs don't exist, we reject -10

3 0
2 years ago
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klasskru [66]

Answer:

37%

Step-by-step explanation:

6 0
2 years ago
Penny and her two friends each ate 1/6 of cake . how much cake did they eat
Hoochie [10]
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2 years ago
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Michael invests USD 20 000 at 9.6% p.a. compounded monthly.
alexandr1967 [171]

Given :

A = 25000

P = 20000

r % = 9.6 % = 0.096

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To Find :

The time taken say t.

Solution :

We know, compound interest is given by :

A=P(1+\dfrac{r}{n})^{n.t}

Taking log both sides :

A=P(1+\dfrac{r}{n})^{n.t}\\\\log\ \dfrac{A}{P}= n.t\times log( 1+\dfrac{r}{n})\\\\t =\dfrac{1}{n}\times \dfrac{log\ \dfrac{A}{P}}{log(1+\dfrac{r}{n})}\\\\\\t=\dfrac{1}{12}\times \dfrac{log\ \dfrac{25000}{20000}}{log(1+\dfrac{0.096}{12})}\\\\\\t=2.33\ years

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2 years ago
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