Yes
I’m assuming 16 is the amount he earned and (-16) is the amount he spent
16 + (-16) = 16-16 = 0
Juan spent the same amount of money as he earned that day and broke even
Given functin is :
![f\left(x\right)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3D%5Csqrt%5B5%5D%7Bx%7D)
We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.
Domain: (-∞,∞)
Range is the set of y-values obtained by plugging values from domain so the range will also same.
Range: (-∞,∞)
If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.
It crosses x and y-axes both at the origin
Hence x-intercept=0 and y-intercept=0
Graph is not symmetric about y-axis hence it can't be EVEN
Graph is not symmetric about origin so it is ODD.
There is no breaking point in the graph so that means it is a Continuous function.
There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.
END behaviour means how y-changes when x approaches infinity.
From graph we can see that when x-approaches -∞ then y also approaches ∞.
when x-approaches +∞ then y also approaches +∞.
The cube has 6 sides, each a square with dimensions 3 by 3,
the area of any of these squares is 3*3=9 square units.
The total area of the cube is 6*9 square units=54 square units
The volume of a cube with side length a is given by :

, thus the volume of the cube-shaped cell is 3*3*3=27 cube units.
(surface area):(volume)=54:27 = 2:1 =2
Answer:
the ratio of the numerical values is 2
(their ratio including units is 2/unit
Answer:
speed=225.75 miles per hour
Step-by-step explanation:
given:
s=301/2
t=2/3
we have,
v=s/t
v=(301/2)/(2/3)
=(301/2)×3/2
=903/4
v=225.75
therefore, speed of car will be 225.75 miles per hour
The correct answer is the choice that you have selected, the third choice.
When, we are looking at the residuals for a regression line, we always want to see the points balance like in the third choice. This means that the equation that we found is right in the middle of the points.