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LenaWriter [7]
2 years ago
12

A 2 L bottle containing only air is sealed at a temperature of 22°C and a pressure of 0.982 atm. The bottle is placed in a freez

er and allowed to cool to -3°C. What is the pressure in the bottle if the volume changes to 1.8 L?
Chemistry
1 answer:
Degger [83]2 years ago
5 0

Answer:

.997 atm

Explanation:

1. Find the combined gas law formula...

(P1V1/T1 = P2V2/T2)

2. Find our numbers...

P1= .982 atm

P2= ? (trying to find)

V1= 2 L

V2= 1.8 L

T1= 22 C = 295 K

T2= -3 C = 270 K

- Note: always use Kelvin. To find Kelving add 273 to ___C.

3. Rearrange formula to fit problem...

(P2=P1V1T2/V2T1)

4. Fill in our values...

P2= .982 atm x 2 L x 270 K / 1.8 L x 295 K

5. Do the math and your answer should be...

.997 atm

- If you need more help or still do not understand please let me know and I would be glad to help!

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Alenkinab [10]

<u>Answer</u>: Conduction, convection, and radiation move energy from the Sun to Earth and throughout Earth.

Without more information about the experiment itself, I would choose the above answer as correct. All the other statements are correct, however none of them relates to the earth distribution processes on Earth. The last statement does.

8 0
1 year ago
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Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution accord
Marina CMI [18]

Answer:

M_{acid}=0.563M

Explanation:

Hello there!

In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the acid to obtain:

M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M

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5 0
2 years ago
If it takes three "breaths" to blow up a balloon to 1.2 l, and each breath supplies the balloon with 0.060 moles of exhaled air,
vesna_86 [32]
<span>It takes 3 breaths to get to 1.2 l. One breath is then (1.2 l) / 3 breaths = .4l/breath. To get to 3.0 l we need the difference from 1.2 l. 3.0-1.2 = 1.8 l. Divide the difference by liters/breath (.4) to get how many needed breaths. (1.8 l)/(.4 l/breath) = 4.5 breaths to get the balloon to 3.0 l. In total there were 3 breaths+ 4.5 breaths = 7.5breaths to get to 3.0 l. To find the total moles multiply 7.5breaths by .060 moles/breath 7.5 breaths*.060moles/breath = .45moles</span>
6 0
2 years ago
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Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
2 years ago
Read 2 more answers
You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain
IrinaVladis [17]

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

Moles of O_2:-

Mass = 49.8 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{49.8\ g}{32\ g/mol}

Moles_{O_2}= 1.55625\ mol

Since pressure and volume are constant, we can use the Avogadro's law  as:-

\frac {V_1}{n_1}=\frac {V_2}{n_2}

Given ,  

V₂ is twice the volume of V₁

V₂ = 2V₁

n₁ = ?

n₂ = 1.55625 mol

Using above equation as:

\frac {V_1}{n_1}=\frac {V_2}{n_2}

\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}

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Molar mass of CO_2 = 44.0 g/mol

Mass of CO_2 = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

<u>34.2 g is the mass of carbon dioxide gas one have in the container.</u>

5 0
1 year ago
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