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2 years ago

In an experiment, the reaction of 100.0 g of iodine produced 144.9 g of a compound formed from iodine and fluorine.

Chemistry

1 answer:

kakasveta [241]2 years ago

7 0

Answer:

a) mass of fluorine consumed = 44.9 g of fluorine

b) mass ratio of iodine to fluorine = 20 : 9 in simplest ratio

c) mass of compound that will be produced = 123.5 g of compound

Explanation:

Equation of reaction: Iodine + Fluorine ---> (Iodine-Flourine) compound

a) According to the law of conservation of mass, mass of reactants = mass of products.

Therefore mass of fluorine consumed = mass of product - mass of iodine reacted

mass of fluorine consumed = 144.9 g - 100.0 g

mass of fluorine consumed = 44.9 g of fluorine

b) mass ratio of iodine to fluorine = 100 : 44.9

mass ratio of iodine to fluorine = 20 : 9 in simplest ratio

c) mass of fluorine that 85.2 g of iodine will react with is given below;

85.2 * (44.9/100) = 38.25 g of fluorine

Therefore, mass of compound that will be produced = (85.2 + 38.25) g

mass of compound that will be produced = 123.5 g of compound

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The answer:
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"The compound K2O2 also exists. A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O

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Answer:

Yes, the chemist can determine which compound is in the sample.

Explanation:

In 1 mole of K₂O, the mass of K is 2 × 39.1 g = 78.2 g and the mass of K₂O is 94.2 g. The mass ratio of K to K₂O is 78.2 g / 94.2 g = 0.830.

In 1 mole of K₂O₂, the mass of K is 2 × 39.1 g = 78.2 g and the mass of K₂O₂ is 110.2 g. The mass ratio of K to K₂O₂ is 78.2 g / 110.2 g = 0.710.

If the chemist knows the mass of K and the mass of the sample, he or she must calculate the mass ratio of K to the sample.

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2 years ago

In the first step of glycolysis, the given two reactions are coupled. reaction 1:reaction 2:glucose+Pi⟶glucose-6-phosphate+H2OAT

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Answer: Reaction 1 is non spontaneous.

Explanation:

According to Gibb's equation:

$\Delta G=\Delta H-T\Delta S$

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When $\Delta G$ = +ve, reaction is non spontaneous

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$\Delta G$ = 0, reaction is in equilibrium

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2 years ago

If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p

Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

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The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

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Therefore,

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10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

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percentage yield of NaCl = 96.635897436%

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