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Sonja [21]
2 years ago
4

Consider a reaction of chemicals depicted as A + B → C + D. Suppose reaction of 17.8 grams of A with 29.5 grams of B gave 24.7 g

rams of C. However, the theoretical yield of C for this reaction was 33.3 grams. What was the percent yield of chemical C?
Chemistry
1 answer:
Yanka [14]2 years ago
8 0

Answer:

The percentage yield of C is 74.2%

Explanation:

Step 1:

Data obtained from the question.

Actual yield of C = 24.7 g

Theoretical yield of C = 33.3 g

Percentage yield of C =?

Step 2:

Determination of the percentage yield of C.

The percentage yield of C can be obtained by applying the following equation:

Percentage yield = Actual yield /Theoretical yield x100

Percentage yield = 24.7/33.3 x 100

Percentage yield = 74.2%

Therefore, the percentage yield of C is 74.2%

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Answer:

The final result is <u>2-methoxybutane. </u>

<u />

Explanation:

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When it will react with methanol, in the presence of an acid, the result will be an ether.

C4H8 + CH3OH → C5H12O

An acid-catalyzed ether synthesis from alkenes is limited by carbocation stability.

In the first step, the double bound will disappear. The C2 atom will be a C+ atom, this becaus it has only 3 bounds and not 4.

This C+ -atom will atract the O- atom to form an ether. The CH3 of methanol will bind on the C3 atom, this is the most stable position.

2-methoxybutane will be formed. It has a structural formula of C5H12O

1-methoxybutane will not be formed, because it's less stable.

1-butanol will be formed when water is added to 1-butene. The mechanism has the same principle but not the same product.

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2 years ago
100 POINTS!!!!Questions/Results Heat energy, Q, is calculated by multiplying the mass of the object in grams, m, by the change o
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2 years ago
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