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DIA [1.3K]
2 years ago
3

In the right triangle shown, m\angle A=45\degreem∠A=45°m, angle, A, equals, 45, degree and AB = 12AB=12A, B, equals, 12. How lon

g is BC

Mathematics
1 answer:
denis23 [38]2 years ago
4 0

Answer:

BC=6\sqrt{2}\ units

Step-by-step explanation:

In this problem i will assume that the side AB is the hypotenuse

The picture in the attached figure

we know that

In a right triangle, if one angle is 45 degrees, then the other angle complementary is equal to 45 degrees too

so

m\angle B=45^o

In the right triangle ABC

cos(B)=\frac{BC}{AB} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

we have

cos(45^o)=\frac{\sqrt{2}}{2}

AB=12\ units

substitute

BC=cos(B)(AB)

BC=\frac{\sqrt{2}}{2}(12)=6\sqrt{2}\ units

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Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.
vodka [1.7K]

Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation (\sqrt[3]{128} )^{x}\\

According to one of the law of indices,

(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}

Applying this law to the question;

(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

5 0
2 years ago
Read 2 more answers
Find the center, vertices, and foci for the ellipse 25x^2 + 64y^2 = 1600
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Equation               25x² + 64y² = 1600

Process

1.- Divide all the equation by 1600

                             25x²/1600 + 64y²/ 1600 = 1600/1600

-Simplify

                              x²/64 + y²/ 25 = 1

2.- Equation of a horizontal ellipse

                             \frac{x^{2} }{a^{2}} + \frac{y^{2}}{b^{2}} = 1

3.- Find a, b and c

    a² = 64             a = 8

    b² = 25             b = 5

-Calculate c with the Pythagorean theorem

                   a² = b² + c²

-Solve for c

                   c² = a² - b²

-Substitution

                   c² = 8² - 5²

-Simplification

                  c² = 64 - 25

                  c² = 39

-Result

                  c = √13

4.- Find the center

          C = (0, 0)

5.- Find the vertices

          V1 = (-8, 0)     V2 = (8, 0)

6.- Find the foci

          F1 = (-√13, 0)   F2 = (√13, 0)

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2 years ago
Which equation describes this line?
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The last equation would best describe the line.

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Answer:

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Step-by-step explanation:

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Length of the left and right sides:

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From point (-2, 1) to point (-1, 0) the slope is:

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If you dilate the smaller quadrilateral by a factor of 3, you get the larger quadrilateral (they have the same slope, and 3 times length of the smaller quadrilateral is equal to the length of the larger quadrilateral).

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The answer is Letter c

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