Answer: 
Step-by-step explanation:
<h3>
The complete exercise is attached.</h3>
You can observe in the picture attached that the box is a rectangular prism.
The volume of a rectangular prism can be found with this formula:

Where "l" is the length, "w" is the width and "h" is the height.
You know that the lenght of each side of those cubes is 1 centimeter. Therefore, you can multiply the number of cubes on each side of the box by 1 centimeter in order to find the lenght, the width and the height of the box:
Now you can substitute the lenght, the width and the height of the box into the formula shown at the beginning of the explanation:

Finally, evaluating, you get that the volume of the box is:

Answer:
Morgan, Dakota and Taylor showed their work solving the equation 7x + 5x +1= 73. Identify the student with the invalid first step and justify your reasoning. Morgan 7x + 5x + 1 = 73 12x + 1 = 73 Dakota 7x + 5x + 1 = 73 7x + 6x = 73 Taylor 7x + 5x + 1 = 73 7x + 5x = 72
Step-by-step explanation:
Answer:
![f(x)=4\sqrt[3]{16}^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D)
Step-by-step explanation:
We believe you're wanting to find a function with an equivalent base of ...
![4\sqrt[3]{4}\approx 6.3496](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B4%7D%5Capprox%206.3496)
The functions you're looking at seem to be ...
![f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x](https://tex.z-dn.net/?f=f%28x%29%3D2%5Csqrt%5B3%5D%7B16%7D%5Ex%5Capprox%202%5Ccdot2.5198%5Ex%5C%5C%5C%5Cf%28x%29%3D2%5Csqrt%5B3%5D%7B64%7D%5Ex%3D2%5Ccdot%204%5Ex%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D%5Capprox%204%5Ccdot%206.3496%5Ex%5C%20%5Cleftarrow%5Ctext%7B%20this%20one%7D%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B64%7D%5E%7B2x%7D%3D4%5Ccdot%2016%5Ex)
The third choice seems to be the one you're looking for.
We know that
[the area of semicircle]=pi*r²/2
for r=3.5 units
[the area of semicircle]=pi*3.5²/2---> 19.24 units²
[the area of the triangle]=b*h/2
b=7 units
h=3 units
[the area of the triangle]=7*3/2-----> 10.5 units²
the area of the figure=19.24+10.50----> 29.74 units²----> 29.7 units ²
the answer is
29.7 units ²
Answer:
Step-by-step explanation:
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