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Free_Kalibri [48]

2 years ago

15

If testing the claim that sigma subscript 1 superscript 2 baseline not equals sigma subscript 2 superscript 2σ21≠σ22, what do w

e know about the two samples if the test statistic is fequals=1?

1 answer:

12345 [234]2 years ago

6 0

Answer:

The statistic for this system of hypothesis is given by:

$F=\frac{s^2_1}{s^2_2}$

If the statistic is equal to 1 then that means $s^2_1 = s^2_2$ and we don't have enough evidence to conclude that the two population variances and deviations are different.

Step-by-step explanation:

System of hypothesis

We want to test if the variation for a group1 is equal to another one 2, so the system of hypothesis are:

H0: $\sigma^2_1 = \sigma^2_2$

H1: $\sigma^2_1 \neq \sigma^2_2$

Calculate the statistic

The statistic for this system of hypothesis is given by:

$F=\frac{s^2_1}{s^2_2}$

If the statistic is equal to 1 then that means $s^2_1 = s^2_2$ and we don't have enough evidence to conclude that the two population variances and deviations are different.

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Abigail gathered data on different schools' winning percentages and the average yearly salary of their head coaches (in millions

11111nata11111 [884]

Answer:

C. On average, each 1 million dollar increase in salary was associated with an 8.42 point increase in winning percentage

Step-by-step explanation:

Apparently, winning percentage is plotted on the vertical axis, so the slope represents the ratio of winning percentage to salary in millions.

Then an increase in salary by 1 million is expected to be associated with an increase of 8.42 points in winning percentage.

3 0

2 years ago

Es urgente ¡¡¡ si la MH de a y 4 es 6 y la MH de 8 y b es 12 calcula la MH de a y b

TiliK225 [7]

Answer:

Sabemos que:

$MH(x, y) = \frac{2xy}{x+y}$

y tenemos que:

$MH (a,4) = \frac{2*a*4}{a+4} = \frac{8*a}{a+4} = 6$

Con esto podemos encontrar el valor de a:

8*a/(a+ 4) = 6

8*a = 6*(a + 4) = 6*a + 24

8a - 6a = 24

2a = 24

a = 24/2 = 12.

Tambien sabemos que:

$MH(8,b) = \frac{2*8*b}{8+b} =\frac{16*b}{8+b} = 12$

Y de ahí podemos despejar b:

(16*b)/(b + 8) = 12

16*b = 12*(b + 8) = 12b + 96

16b - 12b = 96

4b = 96

b = 96/4 = 24

Entonces tenemos a = 12 y b = 24, y el MH de a y b es:

MH(12,24) = 2*12*24/(12 + 24) = 24*24/36 = 16

7 0

2 years ago

In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t

AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

P(X = r) = $\binom{n}{r}p^{r}(1-p)^{n-r}$ for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

r = no. of success which is at least 5 in our case

p = probability of success which is probability of Roman Catholic of

0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= $\binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}$

= 56 * $0.9^{5} * (0.1)^{3}$ + 28 * $0.9^{6} * (0.1)^{2}$ + 8 * $0.9^{7} * (0.1)^{1}$ + 1 * $0.9^{8}$

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0

2 years ago

Forty-two percent of primary care doctors think their patients receive unnecessary medical care (reader's digest, december 2011/

igomit [66]

Answer:

The standard error is 0.02849

Step-by-step explanation:

<u>Explanation:</u>-

given data is 42% of primary case doctors think their patients receive un-necessary medical care.

That is The proportion 'p' = 42% = 0.42

Given sample size is n =300

The standard error of the sampling distribution of the sample proportion is

$se (p) = \frac{\sqrt{p(1-p)} }{\sqrt{n} }$

$se (p) = \frac{\sqrt{0.42(1-0.42))} }{\sqrt{300} }$

use calculator on simplification , we get

standard error = 0.02849

5 0

2 years ago

List the first five terms of the sequence. a1 = 4, an+1 = 5an − 3

RUDIKE [14]

The recursive formula

$a_{n+1} = 5a_n-3$

is telling you that the next term in the sequence is five times the previous one, minus 3.

So, if we start with $a_1=4$ , we have to multiply it by 5 and subtract 3 to get the next:

$a_2 = 5a_1-3 = 5\cdot 4 - 3 = 20-3 = 17$

And similarly we can obtain all the next terms:

$a_3 = 5a_2-3 = 5\cdot 17 - 3 = 85-3 = 82$

$a_4 = 5a_3-3 = 5\cdot 82 - 3 = 410-3 = 407$

$a_5 = 5a_4-3 = 5\cdot 407 - 3 = 2035-3 = 2032$

5 0

2 years ago