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Sophie [7]
2 years ago
11

Which of the following is not true about Machine Learning?Machine Learning was inspired by the learning process of human beings.

Machine Learning models iteratively learn from data, and allow computers to find hidden insights. Machine Learning models help us in tasks such as object recognition, summarization, and recommendation. Machine learning gives computers the ability to make decision by writing down rules and methods and being explicitly programmed.
Engineering
1 answer:
Anton [14]2 years ago
3 0

Answer:

Machine learning gives computers the ability to make decision by writing down rules and methods and being explicitly programmed.

Explanation:

Machine learning algorithms build a mathematical model based on sample data, known as "training data", which it uses to make predictions or decisions without being explicitly programmed to do so.

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Cold feedwater enters a 200-kPa open feedwater heater of a regenerative Rankine cycle at 70°C with a flow rate of 20 kg/s. Bleed
Anni [7]

Answer:

The mass flow rate of bleed steam to be supplied is; m'_s = 1.85 Kg/s

Explanation:

From the first table i attached, at temperature of 70°C, the enthalpy of the cold water feed is;

h_c = 293 KJ/Kg

Also from the same table, at a temperature of 160°C and by interpolation, the enthalpy of the steam is;

h_s = 2790 KJ/Kg

Now, the exiting water is leaving the water heater at a combined rate of m'_c + m'_s and we know that it is a saturated liquid at Pressure of 200 KPa.

Where m'_c is mass flow rate of cold water feed while m'_s is mass flow rate of bleed steam.

Thus, from the second table attached and at 200KPa,the enthalpy of the saturated liquid is;

h_e = 504.71 KJ/kg

Now, from energy balance equation, we have;

E'_e = E'_c + E'_s

(m'_c + m'_s)h_e = (m'_c)h_c + (m'_s)h_s

Plugging in the relevant values, we have;

(20 + m'_s)504.71 = (20)293 + (m'_s)2790

10094.2 + 504.71m'_s = 5860 + 2790m'_s

2790m'_s - 504.71m'_s = 10094.2 - 5860

2285.29m'_s = 4234.2

m'_s = 4234.2/2285.29

m'_s = 1.85 Kg/s

8 0
2 years ago
A Coca Cola can with diameter 62 mm and wall thickness 300 um has an internal pressure of 100 kPa. Calculate the principal stres
GarryVolchara [31]

Answer:

\sigma _1=10.33MPa

\sigma _2=5.16MPa

Explanation:

Given that

Diameter(d)=62 mm

Thickness(t)= 300 μm=0.3 mm

Internal pressure(P)=100 KPa

Actually there is no any shear stress so normal stress will become principle stress.This is the case of thin cylinder.The stress in thin cylinder are hoop stress and longitudinal stress .

The hoop stress

\sigma _h=\dfrac{Pd}{2t}

Longitudinal stress

\sigma _l=\dfrac{Pd}{4t}

Now by putting the values

\sigma _h=\dfrac{Pd}{2t}

\sigma _h=\dfrac{100\times 62}{2\times 0.3}

\sigma _h=10.33MPa

\sigma _l=5.16MPa

So the principle stress are

\sigma _1=10.33MPa

\sigma _2=5.16MPa

4 0
2 years ago
Ethane (C2H6) is burned at atmospheric pressure with a stoichiometric amount of air as the oxidizer. Determine the heat rejected
Amanda [17]

Answer:

heat rejected =-1427820 KJ/mol of C_{2} H_{6}

Explanation:

Fuel ethane C_{2} H_{6}

Burning Temperature = T = 25^{0}

Pressure = P = 1 atm

The stiochiometric equation for this reaction is

C_{2} H_{6} +a_{th} (O_{2} +3.76N_{2}) >>>> 2CO_{2} + 3H_{2}O+3.76a_{th}N_{2}

The enthalpy of the reaction is given as

hc=H_{product} +H_{react}

= \Sigma N_{p} h^{0} _{f.p} -\Sigma N_{r} h^{0} _{f.r}

=\Sigma N_{p} h^{0} _{f.p}-\Sigma N_{r} h^{0} _{f.r}

=(Nh^{0} _{f} )_{CO_{2} }+(Nh^{0} _{f} )_{H_{2}O }-(Nh^{0} _{f} )_{C_{2} }H_{6}

Where

N = number of poles

h^{0} _{f} = enthalpy of formation at the standard reference stateFrom the enthalpy of formation tables  at 25 degrees  and 1 atmTaking enathalpy of formation of [tex]CO_{2} = -393520 KJ/mol

Taking enathalpy of formation of H_{2}O = -241820 KJ/mol

Taking enathalpy of formation of C_{2} H_{6} = -84680 KJ/mol

=(Nh^{0} _{f} )_{CO_{2} }+(Nh^{0} _{f} )_{H_{2}O }-(Nh^{0} _{f} )_{C_{2} }H_{6}

by putting values

hc=(2\times-393520)+(3\times-241820)-(1\times-84680 )\\

hc=-1427820 KJ/mol of C_{2} H_{6}

heat rejected = heat of enthalpy of formation

heat rejected =-1427820 KJ/mol of C_{2} H_{6}

7 0
2 years ago
Only put coolant into your radiator when the engine is _____.
Arada [10]

Only put ciilant into ur radiator when the engine is cool (D)

5 0
2 years ago
1. Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3 is compressed slowly in an isothermal process to a final pressure
Sauron [17]

Answer:

Workdone during the process = 130kJ

Explanation:

Workdone by an expanding gas which is also called pressure-volume work, is defined as the pressure exerted by the gas molecules on the walls of the containing vessel. If work done by an expanding gas is the energy transferred to its surroundings i.e If volume increases, workdone is negative(loses energy).

In an isothermal process(constant Temperature of 300K, we use boyles law:

P1V1 = P2V2

V2 = (150 * 0.2)/800

= 0.0375 m3

W = -P(V2 - V1)

= 800*(0.0375 - 0.200)

= 130kJ

7 0
2 years ago
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