answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rom4ik [11]
2 years ago
4

4. A compound composed of carbon, hydrogen, and chlorine effuses through a pinhole 0.411 times as fast as neon. Select the corre

ct molecular formula for the compound. A. CHCl3 B. CH2Cl2 C. C2H2Cl2 D. C2H3Cl E. CCl4
Chemistry
1 answer:
Mumz [18]2 years ago
5 0

Answer:

Option A. CHCl3

Explanation:

Step 1:

Representation:

Let R1 be the rate of effusion of Neon.

Let R2 be the rate of effusion of the compound

Let M1 be the molar mass of Neon .

Let M2 be the molar mass of the compound

Step 2:

Data obtained from the question. This includes:

Rate of effusion of Ne (R1) = R1

Rate and effusion of the compound (R2) = 0.411 x R1

Molar Mass of Neon (M1) = 20. 18g/mol

Molar Mass of the compound (M2) =?

Step 3:

Determination of the molar mass of the compound.

To obtain the formula of the compound, we need to determine the molar mass of the compound.

Applying the Graham's law of diffusion equation, the molar mass of the compound is obtained as follow:

R1/R2 = √(M2/M1)

R1/0.411 x R1 = √(M2/20.18)

1/0.411 = √(M2/20.18)

Take the square of both sides.

(1/0.411)^2 = M2/20.18

Cross multiply to express in linear form

M2 = (1/0.411)^2 x20.18

M2 = 119.5g/mol

The molar mass of the compound is 119.5g/mol

Step 4:

Determination of the formula of the compound.

To know which option is correct, we'll simply evaluate the options as follows:

For option A:

Molar Mass of CHCl3 = 12 + 1 + (35.5x3) = 12 + 1 + 106.5 = 119.5g/mol

For option B:

Molar Mass of CH2Cl2 = 12 + (2x1)+ (35.5x2)= 85g/mol

For option C.

Molar Mass of C2H2Cl2 = (12x2 + (2x1) + (35.5x2) = 97g/mol

For option D.

Molar Mass of C2H3Cl = (12x2) + (3x1) + 35.5 = 62.5g/mol

For option E.

Molar Mass of CCl4 = 12 + (35.5x4) =

154g/mol

From the above illustration, option A has the same molar mass as the compound. Therefore, option A is the correct answer.

You might be interested in
A 7.591-9 gaseous mixture contains methane (CH4) and butane
mestny [16]

Answer:

65.71%

Explanation:

First, we can write the mass of the mixture, thus:

7.519g = X + Y <em>(1)</em>

<em>Where X is the mass of methane and Y the mass of butane</em>

<em />

Also, the reactions of combustion are:

CH₄ + 2O₂ → CO₂ + 2H₂O

<em>2 moles of oxygen react per mole of methane</em>

C₄H₁₀ + 13/2 O₂ → 4CO₂ + 5H₂O

<em>13/2 moles of oxygen react per mole of methane</em>

<em />

That means, in therms of moles of oxygen we can write:

0.9050 moles = 2X/16.04 + 13/2Y/ 58.12

0.9050 = 0.12469X + 0.11184Y <em>(2)</em>

<em>Where 16.04 and 58.12 are molar masses of methane and butane</em>

That is because if X is the mass of methane:

X g Methane * (1mol / 16.04g) = Moles methane

Moles methane * (2 moles Oxygen / mole methane) = Moles oxygen

Replacing (1) in (2):

0.9050 = 0.12469X + 0.11184 (7.519 - X)

0.9050 = 0.12469X + 0.841 - 0.11184X

0.0641 = 0.01285X

X = 4.988g = Mass of methane.

And mass percent of methane is:

4.988g / 7.591g * 100

<h3>65.71%</h3>

7 0
2 years ago
If you compared 1 m solutions, was a 1 m nacl solution more or less hypertonic than a 1 m sucrose solution? what is your evidenc
igor_vitrenko [27]
When you say the solution is hypertonic, it means that the solution has a higher osmotic pressure. The formula for this is:

P = iMRT,
for strong electrolytes, i = number of ions. 
for nonelectrolytes, i = 1

1. The P for sucrose solution which is a nonelectrolyte (assuming room temp):
P = (1)(1m)(8.314 J/mol-K)(298 K)
P = 2477.572 Pa

The P for NaCl solution, which is a strong electrolyte:
P = (2)(1 m)(8.314)(298 K)
P = 4955.144 Pa

<em>So, that means that NaCl is more hypertonic than the sucrose solution.</em>

2. For the second question, the P for the combination of 1 m glucose (nonelectrolyte) and 1 m sucrose is:
P = (1)(1 m)(8.314)(298 K) + (1)(1)(8.314)(298 K) = 4955.144 Pa
<em>In this case, the osmotic pressures are now equal. It is not hypertonic, but isotonic.</em>

7 0
2 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°C _____.
MatroZZZ [7]

Answer:

c

Explanation:

1 calorie = 4.184J/g×°C

This also happens to be the specific heat capacity of water, which is the amount of energy it takes to raise the temperature of 1mL of water by 1°C

6 0
2 years ago
Carbon monoxide and molecular oxygen react to form carbon dioxide. A 50.0 L reactor at 25.0 oC is charged with 1.00 bar of CO. T
Umnica [9.8K]

Answer:

CO = zero

CO2 =1 bar

O2  = 2.02 bar

Explanation:

We are given

initial pressure of CO = 1bar

total pressure = 3.52 bar

so initial pressure of O2 = 3.52 - 1 = 2.52 bar

the reaction is

2CO + O2 →  2CO2

using the unitary method

2 moles of CO2 → 1 mole of O2

1  bar of CO → \frac{1}{2} * 1= 0.5 bar (required)

but we have more oxygen present , that means CO is the limiting reagent

  • Final pressure of CO will be zero as it is the limiting reagent so it will be consumed completely
  • 1 bar of CO → \frac{2mol CO2}{2mol CO} * 1= 1 bar of CO2
  • 2.52 bar O2 (initially) - 0.5 bar (reacted) = 2.02bar O2
6 0
2 years ago
If a 0.4856 gram sample of khp is dissolved in sufficient water to prepare 250 ml of solution, and 25 ml of the solution require
dangina [55]

Mass of potassium hydrogen pthalate KHP is 0.4856 g, its molar mass is 204.22 g/mol, number of moles of KHP can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass, putting the values,

n=\frac{0.4856 g}{204.22 g/mol}=0.00237 mol

This will be number of moles of NaOH at equivalent point.

Detailed calculations:

Molarity is defined as number of moles in 1 L of solution, for 250 mL of solution, molarity will be:

M=\frac{0.00237 mol}{250 \times 10^{-3}L}=0.009511 M

For 25 mL, apply dilution law as follows:

M_{1}V_{1}=M_{2}V_{2}

Putting the values,

0.009511\times 250=M_{2}\times 25 mL

On rearranging,

M_{2}=\frac{0.009511\times 250}{25}=0.09511 M

Convert molarity into number of moles,

n=M\times V=0.09511 mol/L\times 25\times 10^{-3}L=0.00237 mol

At equivalent point, number of moles of KHP will be equal to NaOH, thus, number of moles of NaOH will be 0.00237 mol.

Calculation for molarity:

Volume of NaOH is 18.75 mL, thus, molarity can be calculated as follows:

M=\frac{n}{V}

Putting the values,

M=\frac{0.00237 mol}{18.75\times 10^{-3}L}=0.1264 M

Therefore, molarity of NaOH is 0.1264 M

7 0
2 years ago
Other questions:
  • What is the ratio of the concentration of potassium ions to the concentration of carbonate ions in a 0.015 m solution of potassi
    12·2 answers
  • A 63 kg object needs to be lifted 7 meters in a matter of 5 seconds. Approximately how much horsepower is required to achieve th
    14·2 answers
  • How much heat is required to increase the temperature of 100.0 grams of iron from 15.0oC to 40.2oC? (The specific heat of iron i
    10·2 answers
  • List four ways you can avoid injury while using HCl and three steps you would take in case of an accidental exposure to HCl need
    6·2 answers
  • From the options provided for each element below, choose the properties that it may have based on its location in the periodic t
    10·2 answers
  • 100 mL of a 0.300 M solution of AgNO3 reacts with 100 mL of a 0.300 M solution of HCl in a coffee-cup calorimeter and the temper
    14·1 answer
  • Can one atom in this type of reaction win the "tug of war"? What might happen if it did?
    10·2 answers
  • A 60.0 mL sample of 0.250 M NaOH is added to a beaker containing 125 mL of 0.120 M HOCl. Ka for HOCl is 3.5 x 10-8 at 25o C. Fin
    6·1 answer
  • Police often monitor traffic with "K-band" radar guns, which operate in the microwave region at 22.235 GHz (1 GHz = 109 Hz). Fin
    7·1 answer
  • Which of the following best describes electrolytes
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!