<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
The answer is... 20, 90, 8
Step-by-step explanation:
What is the range of Charles’s scores?
<h3>20</h3>
What is the median of Charles’s scores?
<h3>90</h3>
What is the IQR of Charles’s scores?
<h3>8</h3>
If you move the graph to its correct spot, your answers will be clear.
I hope this helps!
- sincerelynini
Given:
Total of raffle tickets = 30
Number of tickets Jason bought = 10
Number of prizes = 3
To find:
The probability that Jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away.
Solution:
Total of raffle tickets = 30
Number of prizes = 3
So, number of total outcomes is
Number of tickets Jason bought = 10
So, number of favorable outcomes is
Now,
Therefore, the correct option is A.
Complete question :
En un concesionario de coches hay modelos de varios colores. Los rojos suponen 1/6 del total, los azules, 2/9 del total, y los blancos, 4/15 del total.
a)¿Cuál de esos colores es el más frecuente?
b) Si hay 40 coches azules, ¿cuántos hay en total?
Responder:
Coches blancos
180 coches
Explicación paso a paso:
Dado que:
Rojo = 1/6 del total
Azul = 2/9 del total
Blanco = 4/15 del total
Para determinar qué color es el más alto, convierta los valores en decimal:
1/6 = 0,166667
2/9 = 0,2222
15/4 = 0,26667
Por lo tanto;
4/15> 2/9> 1/6
Por tanto, los coches blancos son los que más
2.)
Sea Número total = x
Por lo tanto,
2/9 de x = 40
2x / 9 = 40
2x = 360
x = 180
Por tanto, hay 180 coches en total.
Answer: The field F has a continuous partial derivative on R.
Step-by-step explanation:
For the field F has a continuous partial derivative on R, fxy must be equal to fyx and since our field F is ∇f,
∇f = fxi + fyj + fzk.
Comparing the field F to ∇f since they at equal, P = fx, Q = fy and R = fz
Since P is fx therefore;
∂P ∂y = ∂ ∂y( ∂f ∂x) = ∂2f ∂y∂x
Similarly,
Since Q is fy therefore;
∂Q ∂x = ∂ ∂x( ∂f ∂y) = ∂2f ∂x∂y
Which shows that ∂P ∂y = ∂Q ∂x
The same is also true for the remaining conditions given
Answer:
21.186%
Step-by-step explanation:
z = (x-μ)/σ,
where
x is the raw score = 2400mg
μ is the population mean = 2000mg
σ is the population standard deviation = 500mg
z = 2400 - 2000/500
z = 0.8
Probability value from Z-Table:
P(x<2400) = 0.78814
P(x>2400) = 1 - P(x<2400) = 0.21186
Converting to percentage:
0.21186 × 100
= 21.186%
Therefore, the percent of the meals
ordered that exceeded the recommended daily allowance of 2400 mg of sodium is 21.186%
