First things first, write the equations!
- Word problems can be intimidating because of all information given, so all you need to focus on, is the information about the variables you are solving, everything else, like the story line is irrelevant!
- Writing Equations from Word Problems:
pull the good stuff (information about the variables) so you can see the information needed, without having to mess your brain up with a bunch of irrelivance!
Equation 1:
3 donuts and 2 coffees is $3.94
Equation 2:
2 donuts and 6 coffees is $7.20
Now it is simply reading the equation...
Knowing these "terms" when writing Equations from a word problem is VERY IMPORTANT;
IS: =
and, more than, etc: +
less than, etc: -
Knowing the terms makes Writing the Equations THE EASIEST PART! Most of the time students get these problems wrong because of wrong equations!
So Equation 1 IS ( = ) ;)
3 Donut + 2 Coffee = 3.94
Equation 2:
2 donut + 6 coffee = 7.20
Now, to make things simple I personally find it easier to "let Donuts = d" and "let Coffee = c"
so...
3d + 2c = 3.94
2d + 6c = 7.20
in order to solve, we have to ELIMINATE one of the variables by making one of them equal 0.
I chose to eliminate c by multiplying the first equation by 3.
3 (3d + 2c = 3.94)
--> 9d + 6c = 3.94
and then the 2nd equation by -1
-1 (2d + 6c = 7.20)
---> -2d + -6c = -7.20
9d + 6c = 11.82
-2d + -6c = -7.20
--- Now we can add the 2 equations, doing so will cancel out c!
9d + 6c = 11.82
+
-2d + -6c = -7.20
= 7d + 0c = 4.62
= 7d = 4.62
now it is simple algebra to figure out d!
- you want to get d by itself so we need to get rid of the 7 and take it to the other side by division!
so-- 7d/7 = 4.62/7
= d = .66
Now that we know d, we just plug it into the original equations to find c!
- you can choose either one to plug it intl , but I chose equation 2:
2(.66) + 6c = 7.20
* MUST DO ORDER OF OPERATIONS- PEMDAS (parentheses, exponemts, multiplication, division, addition and then lastly subtraction)
so first we multiply 2 and .66
1.32 + 6c = 7.20
Now we want to get c by itself, so we subtract 1.32 by both sides-
6c = 5.88
now divide to get c
c = .98
ALWAYS CHECK
BOTH
EQUATIONS AFTER FINDING THE VARIABLES TO ENSURE YOU HAVE THE CORRECT ANSWER (:
I hope that helped (:
<h2>
∴Will ran 13.55 yards more than James.</h2>
Step-by-step explanation:
Given Will ran the diagonal distance across a square field measuring 40 yards each sides .
∴The distance covered by Will was =
yards
= 
yards=56.56 yards
Again James ran diagonal distance across a rectangle field with a length of 25 yards and a width of 35 yards.
So,distance covered by James was =
yards
=
yards = 43.01 yards
∴Will ran longer distance.
∴Will ran 13.55 yards more than James.
Given:
Actual: 9.0 lbs with standard deviation of 0.35 lbs
sample: 8.2 lbs
standard deviation means that the fish caught should be within the range of 8.65 and 9.35
9.00 + 0.35 = 9.35 lbs
9.00 - 0.35 = 8.65 lbs
The sample that had an average weight of 8.2 lbs is not a representative of the population because its weight goes beyond the standard deviation.
Answer:
3.5 cm
Step-by-step explanation:
6x-1=4x+6
6x-4x=1+6
2x=7
x=7÷2
x=3.5
I hope my answer will help you and i guess it's correct
Slope is equal to the change in
y
over the change in
x
, or rise over run.
m = change in y / change in x
The change in
x
is equal to the difference in x-coordinates (also called run), and the change in
y
is equal to the difference in y-coordinates (also called rise).
m = y^2 - y^1 / x^2 x^1
Substitute in the values of
x
and
y
into the equation to find the slope.
m
=
3
−
(
−
6
)
8
−
(
−
15
)
Simplify.
Simplify the numerator.
Tap for more steps...
m
=
9
8
−
(
−
15
)
Simplify the denominator.
Multiply
−
1
by
−
15
.
m
=
9
8
+
15
Add
8
and
15
.
m
=
9/23
