Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
Answer:
58, 37, 9
Step-by-step explanation:
Given:
First term a₁ = 65 and common difference d = - 7
This sequence is arithmetic series and formula for calculating n-th term is:
aₙ = a₁ + (n-1) d
Accordingly
The second term is:
a₂ = 65 + (2-1) (-7) = 65 - 7 = 58
a₂ = 58
The fifth term is:
a₅ = 65 + (5 - 1) (-7) = 65 + 4 · (-7) = 65 - 28 = 37
a₅ = 37
The ninth term is:
a₉ = 65 + (9 - 1) (-7) = 65 + 8 · (-7) = 65 - 56 = 9
a₉ = 9
God with you!!!
Expand the given expression.
22.5 + 7(n - 3.4) = 22.5 + 7*n + 7*(-3.4)
Multiply +7 and -3.4 to obtain - 23.8. Therefore
22.5 + 7(n - 3.4) = 22.5 + 7n - 23.8
Write the constant terms together. Therefore
22.5 + 7(n - 3.4) = 7n + 22.5 - 23.8 = 7n - 1.3
Answer: 7n - 1.3
Given that a is an integer from -22 to 0 such that a is equivalent to 43 (mod 23).
Such a can be obtained as follows:
a = 43 (mod 23) - 23 = 20 - 23 = -3.
Therefore, a = -3.
Start with 90/240, then reduce the fraction
you can reduce by dividing each by 10 to get 9/24
reduce more from there, seeing that each number can be divided by 3
9/3 = 3
24/3 = 8
answer 3/8
