Answer:
b) 20 minutes
Step-by-step explanation:
Tom=0.5Mike
in 15 minutes, Tom will have done 1/2 of the lawn
in 15 minutes, Mike will have done 1/4 of the lawn
in 15 minutes, they will have done 3/4 of the lawn
15/3=5 minutes for 1/4 of the lawn to be done
5x4=20 minutes for the entire lawn

4 is really 2 * 2
12 is reallly 2 * 2 * 3
8 is really 2 * 2 * 2
now, the 2 * 2, is repeated in the factoring, so we use it once only. We still have to account for the extra 2 and 3.
therefore, the LCD will be 2 * 2 * 2 * 3, or 24.
after all the slicing in each tray, all pieces will be equal in length in each tray, and there'll be 24 of them in each tray.
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Answer:
Choice D).
is correct.
Step-by-step explanation:
Given function graph is sinusoidal so let's compare with formula 
We know that amplitude is the height from the center line to the peak (or to the trough). From graph we can see that height from the center line to the peak is 20
So amplitude A=20
In that formula, period is given by 
From graph we see that period is 
So both must be equal


cross multiplying them gives
B=4
Clearly there is no shift so C and D are 0
Now plug these values into formula 


Hence choice D is correct.