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Contact [7]
2 years ago
15

If the hydrogen ion concentration, [H+], in a solution is 4.59 x 10-6 M, what is [OH-]?

Chemistry
1 answer:
atroni [7]2 years ago
6 0

Answer:

2.18x10^-9 M

Explanation:

From the question given,

Hydrogen ion concentration, [H+] = 4.59x10^-6 M

Hydroxide ion, [OH-] =?

The hydroxide ion concentration, [OH-] in the solution can be obtained as follow:

[H+] x [OH-] = 1x10^-14

4.59x10^-6 x [OH-] = 1x10^-14

Divide both side by 4.59x10^-6

[OH-] = 1x10^-14 / 4.59x10^-6

[OH-] = 2.18x10^-9 M

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Which of the following are examples of plasma?
artcher [175]
The answers are "t<span>ails of comets, the ionosphere, and a neon sign." or options A, D, and E. Tails of comments are mainly made of plasma. Ice cubes are examples of a solid. A gas fire key word gas is example of a gas. The ionosphere is also mainly made of plasma. A neon sign uses plasma in order to work. A flashlight uses a light bulb which isn't a example of plasma therefore  thats a no.

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2 years ago
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What is the identity of a sample that has a mass of 2.44 g and a volume of 0.34 cm3?
borishaifa [10]
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3 0
2 years ago
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Find the molarity of 186.55 g of sugar (C12H22O11) in 250. mL of water.
Anna [14]

Answer:

The molarity of this sugar solution in water is 2.18 M

Explanation:

Step 1: Data given

Mass of sugar (C12H22O11) = 186.55 grams

Molar mass of C12H22O11 = 342.3 g/mol

Volume of water = 250.0 mL = 0.250 L

Step 2: Calculate moles sugar

Moles sugar = mass sugar / molar mass sugar

Moles sugar = 186.55 grams / 342.3 g/mol

Moles sugar = 0.545 moles

Step 3: Calculate molarity of the sugar solution

Molarity = moles sugar / volume of water

Molarity = 0.545 moles / 0.250 L

Molarity = 2.18 MThe molarity of this sugar solution in water is 2.18 M

6 0
2 years ago
Modern commercial airliners are largely made of aluminum, a light and strong metal. But the fact that aluminum is cheap enough t
Dafna11 [192]

Answer:

The plane with aluminium can lift more mass of passangers than the plane of steel.

Explanation:

The total mass the airplane canc lift is:

m_{tot}=m_{fuselage}+m_{passangers}

For aluminium:

m_{tot}=m_{fus-Al}+m_{pas-Al}

m_{fus-Al}=\delta _{Al}*V_{fuselage}

and

V_{fuselage}=\frac{\pi *L}{4}*[D^2-(D-e)^2]

where:

  • L is lenght
  • D is diameter
  • e is thickness

m_{tot}=\delta _{Al}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Al}

For steel (same procedure):

m_{tot}=\delta _{Steel}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Steel

Knowing that the total mass the airplane can lift is constant and that aluminum has a lower density than the steel, we can afirm that the plane with aluminium can lift more mass of passangers.

Also you can estimate an average weight of passanger to estimate a number of passangers it can lift.

5 0
2 years ago
An irregularly shaped solid which has a mass of 10.283g was placed in a graduated cylinder containing an inert liquid. The initi
Gwar [14]
Liquid  + Solid = 8.89 mL
V ( Solid ) = 8.89 mL - 6.26 mL = 2.63 mL
The density of the solid = m / V = 10.283 g / 2.63 mL =
= 3.9 g/mL = 3.9 g / cm³
3 0
2 years ago
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