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maw [93]
2 years ago
10

Ella has 22 beads Lauren has fewer beads than Ella how many beass might Lauren have

Mathematics
1 answer:
Ad libitum [116K]2 years ago
5 0
Lauren can have as many as 21 one beads to 1 bead
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The distance d (in miles) that you can see to the horizon with your eye level h feet above the water is given by d=3h2−−−√. You
liubo4ka [24]

Answer: He cannot see a ship that is 4.5 miles away.

Step-by-step explanation:

Since we have given that

d=3\sqrt{h}

Here, h is the eye level above the water

d is the distance away.

If h = 12 feet

We will get :

d=3\sqrt{12}\\\\d=3\times 2\sqrt{3}\\\\d=6\sqrt{3}\\\\d=10.39

Hence, it is 10.39 feet away when eye level is 12 feet above the water.

Therefore , he cannot see a ship that is 4.5 miles away.

7 0
1 year ago
In a new card game, you start with a well-shuffled full deck and draw 3 cards without replacement. If you draw 3 hearts, you win
lyudmila [28]

Answer:

Expected pay winning $50= $0.585

Expected pay winning $25= $2.36

Expected pay for anything else= $-4.35

Expected returns=3.59

Expected value for one play= $(-1.41)

Do not play this game because you will lose $1.41

Step-by-step explanation:

Probability P(3 hearts) = (13/52)×(12/51)×(11/50) = 0.013

Probability P(3black)= (26/52)×(24/51)×(23/50) = 0.118

Probability P(drawing anything else)= 1 - 0.013 - 0.118= 0.869

Expected pay($50)= 0.013$(50-5)= $ 0.585

Expected pay($25)= 0.118(25-5)$ = $2.36

Expected pay for anything else= 0.869(0-5)$ =$(-4.347)

Expected value of one play=$ (0.585 + 2.353 -4.347) = -$1.41

c) Do not play the game.

6 0
1 year ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation yo
Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
1 year ago
Read 2 more answers
Jackson is conducting an experiment for his Physics class. He attaches a weight to the bottom of a metal spring. He then pulls t
olga55 [171]
We have that the spring is going to have a sin or a cos equation. We have that the maximum distance of the spring is 6 inches and it is achieved at t=0. Let's fix this as the positive edge. Until now, we have that the function is of the form:
6sin(at+B). We have that the period is 4 minutes and hence that the time component in the equation needs to make a period (2pi) in 4 minutes. Thus 4min*a=2p, a=2p/4=pi/2. In general, a=2pi/T where a is this coefficient, T is the period. Finally, for B, since sin(pi/2)=1, we have that B=pi/2 because when t=0, we have that 6sin(B)=6. Substituting, we have f(t)=6sin(pi*t/2+pi/2)=6cos(pi*t/2)
by trigonometric identities.
7 0
1 year ago
Read 2 more answers
in one month, Jason earns $32.50 less than twice the amount Kevin earns Jason earns $212.50 write and solve an algebraic equatio
hoa [83]
So what I did was as $32.50 twice and got $65.00 and subtracted it with $212.50 and got $152.50. Hope i was helpful!
4 0
2 years ago
Read 2 more answers
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