The first two rows of coefficients are identical, so by inspection, the determinant is 0.
2x+4x-4=2+4x
2x+4x-4x=2+4
2x=6
x=3
25-x=15-3x-10
3x-x= 15-10-25
2x= -20
x= -10
4x=2x+2x+5x-5x
2x+2x+5x-5x-4x
0 . no solution
Answer:
<u>The rabbit could be at eight different numbers of the number line:</u>
<u>-7, - 5, - 3, - 1, 1, 3, 5, and 7.</u>
Step-by-step explanation:
Let's simulate each of the jumps of the rabbit in all the possible directions, as follows:
Option 1: - 4 - 2 - 1 = -7
Option 2: - 4 - 2 + 1 = -5
Option 3: - 4 + 2 - 1 = - 3
Option 4: - 4 + 2 + 1 = - 1
Option 5: 4 - 2 - 1 = 1
Option 6: 4 - 2 + 1 = 3
Option 7: 4 + 2 - 1 = 5
Option 8: 4 + 2 + 1 = 7
The most accurate would be the second statement: <span>The graph is misleading because it uses 3-dimensional bars.
The vertical range is just enough. It only appears small because the bars are in 3D. It should have been in 2D so that we could directly trace it to how much frequency each category is. Even the axes are in 3D also.</span>
