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aivan3 [116]
2 years ago
4

Electromagnetic radiation is emitted when a charged particle moves through a medium faster than the local speed of light. This r

adiation is known as Cerenkov radiation. Cerenkov radiation is found in many interesting places such as particle detectors and nuclear reactors and can even be seen by astronauts when cosmic rays traverse their eyes. It should be stressed that the particle is never going faster than the speed of light in vacuum (or c), just faster than the speed of light in the material (which is always less than c). The creation of Cerenkov radiation occurs in much the same way that a sonic boom is created when a plane is moving faster than the speed of sound in the air. The various wavefronts that propagate in the material add coherently to create an effective shock wave. In this problem, you will become familiar with this type of radiation and learn how to use its properties to get information about the particles that created it.
A)What is the threshold velocity v_threshold (water) (i.e., the minimum velocity) for creating Cerenkov light from a charged particle as it travels through water (which has an index of refraction of n=1.33)?
v_threshold (water) =c
B)What is the threshold velocity v_threshold (ethanol) for creating Cerenkov light from a charged particle as it travels through ethanol (which has an index of refraction of n=1.36)?
v_threshold (ethanol) =c
C)Which of the following best explains why neutrally charged particles can't give off Cerenkov radiation?
a) Neutral particles are too heavy to emit radiation.
b) Neutral particles don't interact with the electromagnetic fields of the medium.
c) Neutral particles can't move above the threshold velocity for Cerenkov radiation.
d) Charged particles hit the nuclei of the material more often and thus create more radiation
Physics
1 answer:
9966 [12]2 years ago
5 0

Answer:

If the particle moves in a medium with velocity and we describe the ratio between the velocity of the particle and the velocity of light as shown below:-

Explanation:

β = vp / c

Where the speed of light is c.

n is the refractive index of the medium.

And the light waves emitted

vem = c /n.

(a) threshold velocity is just   (1/n) c      

So,

          (1/1.33) c =0.752C

(b)  (1/1.36) c =0.735C

(c) Neutral particles do not interfere with the medium's electromagnetic fields.

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A 0.250 kgkg toy is undergoing SHM on the end of a horizontal spring with force constant 300 N/mN/m. When the toy is 0.0120 mm f
konstantin123 [22]

Answer:

(a) The total energy of the object at any point in its motion is 0.0416 J

(b) The amplitude of the motion is 0.0167 m

(c) The maximum speed attained by the object during its motion is 0.577 m/s

Explanation:

Given;

mass of the toy, m = 0.25 kg

force constant of the spring, k = 300 N/m

displacement of the toy, x = 0.012 m

speed of the toy, v = 0.4 m/s

(a) The total energy of the object at any point in its motion

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²

E = 0.0416 J

(b) the amplitude of the motion

E = ¹/₂KA²

A = \sqrt{\frac{2E}{K} } \\\\A = \sqrt{\frac{2*0.0416}{300} } \\\\A = 0.0167 \ m

(c) the maximum speed attained by the object during its motion

E = \frac{1}{2} mv_{max}^2\\\\v_{max} = \sqrt{\frac{2E}{m} } \\\\v_{max} = \sqrt{\frac{2*0.0416}{0.25} } \\\\v_{max} = 0.577 \ m/s

8 0
2 years ago
A man pushes his child in a grocery cart. The total mass of the cart and child is 30.0 kg. If the force resisting the carts moti
-BARSIC- [3]

The force applied by the man is 60 N

Explanation:

We can solve this problem by applying Newton's second law, which states that:

\sum F = ma (1)

where

\sum F is the net force acting on the child+cart

m is the mass of the child+cart system

a is their acceleration

In this problem, we have:

m = 30.0 kg is the mass

a=1.50 m/s^2

And there are two forces acting on the child+cart system:

  • The forward force of pushing, F
  • The force resisting the cart motion, R = 15.0 N

Therefore we can write the net force as

\sum F = F -R

where R is negative since its direction is opposite to the motion

So eq.(1) can be rewritten as

F-R=ma

And solving for F,

F=ma+R=(30.0)(1.50)+15.0=60 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

4 0
2 years ago
A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
Setler [38]

Answer

given,

mass of the ball = 3 kg

swing in vertical circle with radius = 2 m

   work done by the gravity = ?          

   work done by the tension = ?            

Work done by the gravity = - m g Δh            

 Δ h = 2 + 2 = 4 m                                                                

Work done by the gravity =- 3 \times 9.8 \times 4

                                           = -117.6 J                  

work done by gravity is equal to -117.6 J            

Work done by tension will be equal to zero.        

Zero because tension is always perpendicular to velocity

work done by tension is equal to 0 J                          

7 0
2 years ago
¿Alguien me puede ayudar? Problema: Un niño le pide gastada a su papá y éste le contesta que le dará los $120 que tiene en su bo
VLD [36.1K]

Answer: there are 15 coins of $2 and 18 coins of $5

Explanation:

I will answer in English.

X is the number of $5 coins.

Y is the number of $2 coins.

We have the system of equations:

Y + X = 33

Y*2 + X*5 = 120

first, we must isolate one of the variables in one of the equations and then replace it in the other equation, let's isolate Y in the first equation:

Y = 33 - X.

Then we can replace it in the other equation:

(33 - X)*2 + X*5 = 120

66 - X*2 + X*5 = 120

X*3 = 54

X = 54/3 = 18

and using the equation for Y.

Y = 33 - X = 33 - 18 = 15

So there are 15 coins of $2 and 18 coins of $5

3 0
2 years ago
What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect?
erma4kov [3.2K]

<span>E = h x f </span>

<span>. . . then : </span>

<span>f = E / h </span>
<span>f = 4,41•10^-19 / 6,62•10^-34 </span>
<span>f = 6,66•10^14 Hz (s^-1) </span>


<span>b/ What is the wavelength of this light ? </span>
<span>- - - - - - - - - - - - - - - - - - - - - - - - - - - - </span>

<span>λ = c / f </span>
<span>λ = 3•10^8 / 6,66•10^14 </span>
<span>λ = 4,50•10^-7 m </span>
4 0
2 years ago
Read 2 more answers
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