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Vladimir79 [104]
2 years ago
10

Given that, in a certain school, the following are true, what is the probability that a student is taking math or computer scien

ce?
1. The probability that a student is taking math is 33%.
2. The probability that a student is taking computer science is 62%.
3. The probability that a student is taking math and computer science is 58%.
Mathematics
1 answer:
Serhud [2]2 years ago
8 0

Answer:

The probability that a student is taking math or computer science is 0.37

Step-by-step explanation:

The probability that a student is taking math =P(M)=33% =0.33

The probability that a student is taking computer science =P(C)= 62%=0.62

The probability that a student is taking math and computer science =P(M∩C)= 58%=0.58

So, the probability that a student is taking math or computer science i.e.P(M∪C)

So, Formula:P(A∪B)=P(A)+P(B)-P(A∩B)

P(M∪C)=P(M)+P(C)-P(M∩C)

P(M∪C)=0.33+0.62-0.58

P(M∪C)=0.37

Hence the probability that a student is taking math or computer science is 0.37

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A Washington, D.C., "think tank" announces the typical teenager sent 67 text messages per day in 2017. To update that estimate,
creativ13 [48]

Answer:

We reject the null hypothesis and fail to accept it and update that estimate that typical teenager sent does not 67 text messages per day.      

Step-by-step explanation:

We are given the sample:

51, 175, 47, 49, 44, 54, 145, 203, 21, 59, 42, 100

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{990}{12} = 82.5

Sum of squares of differences = 992.25 + 8556.25 + 1260.25 + 1122.25 + 1482.25 + 812.25 + 3906.25 + 14520.25 + 3782.25 + 552.25 + 1640.25 + 306.25 = 3539.363636

S.D = \sqrt{\frac{3539.363636}{11}} = 59.5

We are given the following in the question:  

Population mean, μ =67

Sample mean, \bar{x} = 82.5

Sample size, n = 12

Alpha, α = 0.05

Sample standard deviation, s = 59.5

First, we design the null and the alternate hypothesis

H_{0}: \mu = 67\\H_A: \mu > 67

We use One-tailed t test to perform this hypothesis.

b) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n-1}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{82.5 - 67}{\frac{59.5}{\sqrt{11}} } = 0.864 Now,

t_{critical} \text{ at 0.05 level of significance, 11 degree of freedom } = 1.795

a) Since,                

t_{stat} < t_{critical}

We reject the null hypothesis and fail to accept it and update that estimate that typical teenager send more than 67 text messages per day.

5 0
1 year ago
A pencil and a ruler cost $1.50 together. The ruler costs $1.00 more than the pencil. How much does the pencil cost?
saveliy_v [14]
The pencil costs $0.25.

One way to deduce this is to divide 1.50 by 2 (equaling 0.75) and then subtracting .5 to get 0.25 because if it's $1 more, then the ruler would cost 0.75 + 0.5 and the pencil would cost 0.75 - 0.5, making a total of $1.50.

Another way is to make it an equation. Let's say the ruler is r dollars and the pencil is p dollars.
r + p = 1.50
r = p + 1.00
If we know these two equations, then you can substitute p + 1.00 in the 1st equation (instead of r). This gets us:
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You can simplify this into:
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Then you subtract 1.00 from both sides:
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And you divide 2 from both sides:
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Getting you the answer of:
The pencil costs $0.25

Hope this helps! :)
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1 year ago
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the arc length is:
 
arc = 1.76 cm
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