Answer:
x = -1 and x = 5
Step-by-step explanation:
<em>What are the solutions of the equation (x – 3)² + 2(x – 3) -8 = 0? Use u substitution to solve.</em>
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(x – 3)² + 2(x – 3) -8 = 0 -------------------------------------------------------(1)
To solve this problem, we will follow the steps below;
let u = x-3
we will replace x-3 by u in the given equation:
(x – 3)² + 2(x – 3) -8 = 0
u² + 2u -8 = 0 ----------------------------------------------------------- --------------(2)
We will now solve the above quadratic equation
find two numbers such that its product gives -8 and its sum gives 2
The two numbers are 4 and -2
That is; 4×-2 = -8 and 4+(-2) = 2
we will replace 2u by (4u -2u) in equation (2)
u² + 2u -8 = 0
u² + 4u - 2u -8 = 0
u(u+4) -2(u+4) = 0
(u+4)(u-2) = 0
Either u + 4 = 0
u = -4
or
u-2 = 0
u = 2
Either u = -4 or u = 2
But u = x-3
x = u +3
when u = -4
x = u + 3
x = -4 + 3
x=-1
when u = 2
x = u + 3
x = 2 + 3
x=5
Therefore, x = -1 and x =5
x
For this case we have a function of the form:
y = f (x)
Where,
x: independent variable
y: dependent variable
To answer the question, we must see in the table the values of the independent variable x, for which the values of the dependent variable f (x) are negative.
We have then that the interval that fulfills this condition is from minus infinity to minus 4 without including the 4.
Thus,
(–∞, –4)
Answer:
The entire interval over which the function, f(x), is negative is:
D) (–∞, –4)
Answer:

Step-by-step explanation:
we know that
The absolute value function has two solutions
Observing the graph
the solutions are
and 
First solution (case positive)
assume the symbol of the first solution and then compare the results




Second solution (case negative)

Multiply by -1 both sides

substitute the value of b and compare the results


-------> is correct
Answer:
Step-by-step explanation:
I need help my self♀️