<h2>
Therefore he took 40 gram of
type solution and 10 gram of
type solution.</h2>
Step-by-step explanation:
Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .
Let he took x gram solution of
type solution
and he took (50-x) gram of
type solution.
Total amount of alcohol =
gram
Total amount of solution = 50 gram
According to problem
⇔![\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Bx%5Ctimes%5Cfrac%7B13%7D%7B100%7D%5D%20%2B%5B%2850%20-x%29%20%5Ctimes%5Cfrac%7B18%7D%7B100%7D%20%5D%7D%7B50%7D%3D%20%5Cfrac%7B14%7D%7B100%7D)
⇔
⇔- 5x= 700 - 900
⇔5x = 200
⇔x = 40 gram
Therefore he took 40 gram of
type solution and (50 -40)gram = 10 gram of
type solution.
Answer:
6.33
Step-by-step explanation:
Here, we are asked to give a residual value at x = 3
This mean we are to predict the value of y at the point x= 3
To do this, what we need to do is to input the value x = 3 into the line of best fit equation.
The line of best fit equation according to the question is;
y=0.331986x+5.33286
Substituting x here, we have
y = 0.331986(3) + 5.33286
y = 0.995958 + 5.33286 = 6.328818
Question asks to give answer to the nearest hundredth and that is 6.33
Answer:
A. on edge 2020
Step-by-step explanation:
C. 3:00 p.m.
Low tide occurred at 5:00 a.m. (t=5) and the graph shows that high tide occurred at both 12:00 a.m. (t=0) and 10:00 a.m. (t=10).
That means that between high tide and low tide, 5 hours pass (5-0=5 and 10-5=5).
So if the last high tide was at 10:00 a.m., the next low tide will happen another 5 hours later. 5 hours after 10:00 a.m. is 3:00 p.m.