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Svet_ta [14]
2 years ago
3

Identifying Ways Rocks Change in the Rock Cycle Cycle of a rock. Arrows point from one stage to the next. Stage A, small, brown

granules, to Compaction and cementation or Stage C. Arrow labeled Heat and pressure from Stage C to B, larger gray rocks. Arrow labeled Melting from Stage B to Magma. Arrow labeled Cooling from Magma to Igneous Rock. Arrow labeled Melting from Igneous Rock to Magma. Stage D arrows from Igneous Rock to Stage A, from Stage B to A, and from Stage C to A. Using the drop-down menus, label the parts of the rock cycle.
A- sediment, sedimentary rock, or metamorphic rock
B- sediment, sedimentary rock, or metamorphic rock
C- sediment, sedimentary rock or metamorphic rock
D- compaction and cementation, heat and pressure, or weathering and erosion
Chemistry
2 answers:
Stolb23 [73]2 years ago
9 0

Answer:

A) Sediment

B) Metamorphic rock

C) Sedimentary rock

D) Weathering and Erosion

Explanation:

This is correct on Edge 2020

5 Stars, please!

Make sure to click that heart if this helped!

zhuklara [117]2 years ago
7 0

Answer:

sediment, metamorphic rock, sedimentary rock, weathering and erosion

Explanation:

for edge 2020

hope this helps

HAVE A GREAT DAY : )

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2.478 g of white phosphorus was used to make phosphine according to the equation: P₄(s) + 3OH⁻(aq) + 3H₂O(l) → PH₃(g) + 3H₂PO₂⁻(
prohojiy [21]

<u>Answer:</u> The amount of white phosphorus is 0.0199 moles

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of white phosphorus = 2.478 g

Molar mass of white phosphorus = 124 g/mol

Putting values in above equation, we get:

\text{Moles of white phosphorus}=\frac{2.478g}{124g/mol}=0.0199mol

Hence, the amount of white phosphorus is 0.0199 moles

3 0
2 years ago
How many grams of NH3 are needed to provide the same number of molecules as in 0.35 g of SF6 ?
Strike441 [17]

Answer:

<u />

  • <u>There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.</u>

<u />

Explanation:

Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.

<u>1. Find the molar mass of SF₆:</u>

Atom   atomic mass          number of atoms   total mass in 1 mole

S           32.065 g/mol                     1                                       32.065 g

F            18.998 g/mol                     6                 6 × 18.998 = 113.988 g

                                                                               =====================

                                                          molar mass of SF₆ =    146.053 g/mol

<u>2. Find the number of moles in 0.35 g of SF₆:</u>

  • number of moles = mass in grams / molar mass
  • number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol

<u>3. Find the molar mass of NH₃:</u>

Atom   atomic mass          number of atoms   total mass 1 mole                

N           14.007 g/mol                     1                                       14.007 g

H             1.008 g/mol                    3               3 × 1.008 g = 113.988 g

                                                                               =====================

                                                         molar mass of NH₃ =    17.031 g/mol

<u />

<u>4. Find the mass in 0.0024 mol of NH₃:</u>

  • mass in grams = number of moles × molar mass

  • mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams

<u>5. Conclusion: </u>

There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

6 0
2 years ago
What are the missing coefficients for the skeleton equation below? cr(s) + fe(no3)2(aq) → fe(s) + cr(no3)3(aq)?
strojnjashka [21]
SThe  missing   coefficient  for  the  skeleton   equation  below  is  as  follows

skeleton   equation

Cr(s)  +  Fe(No3)2(aq)  ------> Fe (s)   +  Cr(NO3)3  (aq)
the  missing  coefficient  are  is   as  follows

 2 Cr(s)   +  3  Fe(NO3)2  ---> 3 Fe (s)  +  2 Cr(NO3)3

This  is  obtained   by  making  sure  all  the   molecules  are  balanced  in  both  sides
8 0
2 years ago
27. Scott travels north 5 miles and then goes west 3 miles before coming straight back south 2 miles. What is his distance? *
belka [17]

Scott traveled 10 miles in his journey.

<u>Explanation</u>:

Scott first travels 5 miles in north direction, then he turns to west and covers 3 miles distance finally he turns to south and travels 2 miles. We need to find the total distance covered by the Scott. To find the distance we should sum up all the distances he covered in three directions 5 miles north + 3 miles west + 2 miles south = 10 miles.

Therefore we can conclude that the total distance traveled by the Scott is 10 miles.  

5 0
2 years ago
If 5.61 g of ammonium nitrate (NH4NO3) is dissolved in 155 mL of water to make an instant cold pack, what is the molarity of the
kifflom [539]

Answer:

0.452 M

Explanation:

Remember that to get molarity, you have to go thru an equation:

M=mol/V (in liters)

So...

5.61 g NH4NO3 x 1 mol NH4NO3/80.043 g

=0.0701 mol NH4NO3

Convert mL to L

=155--->0.155 L

Plug in and divide.

0.0701/0.155

=0.452 M

7 0
2 years ago
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