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notka56 [123]
2 years ago
3

How many atoms of vanadium are in 1.28 grams of vanadium

Chemistry
1 answer:
Solnce55 [7]2 years ago
5 0
I hope this helped. It should be right!

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If the speed of a vehicle increases by 22%, by what factor does its kinetic energy increase?
Mila [183]

Answer:

The kinetic increases by 48.84 %

Explanation:

The expression for the kinetic energy is:-

K.E.=\frac{1}{2}\times mv^2

Where, m is the mass of the object

v is the velocity of the object

Let the new velocity is:- v'

v is increased by 22 %. Thus, v' = 1.22 v

So, the new kinetic energy is:-

K.E.'=\frac{1}{2}\times mv'^2=\frac{1}{2}\times m{1.22}^2=\frac{1}{2}\times mv^21.4884=1.4884K.E.

<u>Thus, the kinetic increases by 48.84 %</u>

7 0
2 years ago
Read 2 more answers
Marianne designs an experiment involving electrically charged objects. She wants to know which objects will be attracted to a ne
svet-max [94.6K]

Answer:

When one object is rubbed against another, static electricity can be created. This is because the rubbing creates a negative charge that is carried by electrons. The electrons can build up to produce static electricity. For example, when you shuffle your feet across a carpet, you are creating many surface contacts between your feet and the carpet, allowing electrons to transfer to you, thereby building up a static charge on your skin. When you touch another person or an object, you can suddenly discharge the static as an electrical shock.

Similarly, when you rub a balloon on your head it causes opposite static charges to build up both on your hair and the balloon. Consequently, when you pull the balloon slowly away from your head, you can see these two opposite static charges attracting one another and making your hair stand up.

Materials

• Balloon

• An object made out of wool (such as a sweater, scarf, blanket or ball of yarn)

• Stopwatch

• A wall

• A partner (optional)

Preparation

• Blow up the balloon and tie off the end.

• Have your partner prepare to use the stopwatch.

Procedure

• Hold the balloon in a way that your hand covers as little of its surface area as possible, such as by using only your thumb and pointer finger or by gripping the balloon by its neck where it is tied off.

• Rub the balloon on the woolly object once, in one direction.

• Hold the balloon up on the wall with the side that was rubbed against the wool facing the wall, then release it. Does the balloon stay stuck on the wall? If the balloon stays stuck, have your partner immediately start the stopwatch to time how long the balloon remains bound to the wall. If the balloon does not stick, move to the next step.

• Touch the balloon to a metal object. Why do you think this is important to do?

• Repeat the above process but each time increase the number of times you rub the balloon on the woolly object. Rub the balloon in the same direction each time. (Do not rub the balloon back and forth.)

Observations and results

In general, did the balloon stick to the wall for a longer amount of time as you increased the number of times you rubbed the balloon on the woolly object?

Wool is a conductive material, which means it readily gives away its electrons. Consequently, when you rub a balloon on wool, this causes the electrons to move from the wool to the balloon's surface. The rubbed part of the balloon now has a negative charge. Objects made of rubber, such as the balloon, are electrical insulators, meaning that they resist electric charges flowing through them. This is why only part of the balloon may have a negative charge (where the wool rubbed it) and the rest may remain neutral.

When the balloon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall. Although the wall should normally have a neutral charge, the charges within it can rearrange so that a positively charged area attracts the negatively charged balloon. Because the wall is also an electrical insulator, the charge is not immediately discharged. However, because metal is an electrical conductor, when you rub the balloon against metal the extra electrons in the balloon quickly leave the balloon and move into the metal so the balloon is no longer attracted and does not adhere.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST

6 0
2 years ago
Read 2 more answers
Based on the values you obtained for δh∘rxn, which of the reactions would you expect to be thermodynamically favorable and which
QveST [7]
Following reactions are involved in present reaction
1) A<span>g+(aq)   +    Li(s)     →       Ag(s)     +       Li+(aq)      </span><span>−      384.4kJ
2) </span><span>2Fe(s)     +     2Na+(aq)      →        Fe2+(aq)      +       2Na(s)     +   392.3kJ
</span>3)  <span>2K(s)     +      2H2O(l)      →      2KOH(aq)       +H2(g)       −393.1kJ

In above reaction, reaction 1 and 3 has negative value of </span>δh∘f, while reaction 2 has posiyive value of <span>δh∘f. As per the sign convention positive sign indicates that heat is given out during the reaction, while negative sign indicates heat is to be supplied for reaction to occur. In alternative words, product formed in reaction 2 is stable as compared to reactant. Hence, it is thermodynamically favorable. </span>
7 0
2 years ago
At the beginning of the school year, a chalk company receives an order for 2000 boxes which is the largest order ever placed. Ea
lys-0071 [83]

Answer:

  • <u>259,000 g of chalk.</u>

Explanation:

<u>1) Data:</u>

a) 2000 boxes

b) 175 g / box

c) % yield = 74%

<u>2) Formula: </u>

  • % yield = (theoretical yield / actual yield) × 100

<u>3) Solution:</u>

a) Calcualte the actual yield:

  • mass of product = 2000 box × 175 g/ box = 350,000 g

b) Solve for the theoretical yield from the % yield formula:

  • % yield = (theoretical yield / actual yield) × 100

        ⇒ theoretical yield = % yield × actual yield / 100

             theoretical yield = 74% × 350,000g / 100 = 259,000 g

6 0
2 years ago
What is the balanced equation for the reaction of aqueous cesium sulfate and aqueous barium perchlorate?
Aleksandr-060686 [28]

Answer:

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

Explanation:

When aqueous cesium sulfate and aqueous barium perchlorate are mixed together it gives white precipitate barium sulfate and aqueous solution od cesium perchlorate.

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

According to reaction, 1 mole of cesium sulfate reacts with 1 mole of barium perchlorate to give 1 mole of a white precipitate of barium sulfate and 2 moles of cesium perchlorate.

3 0
2 years ago
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