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ladessa [460]
2 years ago
15

What is the balanced equation for the reaction of aqueous cesium sulfate and aqueous barium perchlorate?

Chemistry
1 answer:
Aleksandr-060686 [28]2 years ago
3 0

Answer:

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

Explanation:

When aqueous cesium sulfate and aqueous barium perchlorate are mixed together it gives white precipitate barium sulfate and aqueous solution od cesium perchlorate.

The balanced chemical reaction is given as:

Cs_2SO_4(aq)+Ba(ClO_4)_2(aq)\rightarrow BaSO_4(s)+2CsClO_4(aq)

According to reaction, 1 mole of cesium sulfate reacts with 1 mole of barium perchlorate to give 1 mole of a white precipitate of barium sulfate and 2 moles of cesium perchlorate.

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<span>The saturated vapor pressure of pure water at 20 ° C is 18 mmHg. If at the same temperature as much as 120 grams of x-substance dissolved in 990 grams of water, the vapor pressure of the solution becomes 17.37 mmHg, calculate the relative molecular mass of the substance x?</span>
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Sample (3.585g) contains 1.388g of C, 0.345g of H, 1.850g of O and its molar mass is 62g. What is the molecular formula of this
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Answer: C2H6O2

Explanation: solution attached:

First convert mass to moles.

Second divide each moles on the lowest amount to find the number of atoms in the empirical formula.

Third calculate the empirical formula mass.

Fourth calculate for the molecular formula by dividing the molar mass over the empirical formula mass.

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A cell was set up having the following reaction Mg(s) + Cd2+ (aq) → Mg2+ (aq) + Cd (s) E°cell = 1.97 V The Magnesium electrode w
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Answer : The concentration of unknown Cd^{2+} will be, 1.807\times 10^{-6}M

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The balanced cell reaction will be,  

Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)

Here magnesium (Mg) undergoes oxidation by loss of electrons, thus act as anode. Cadmium (Cd) undergoes reduction by gain of electrons and thus act as cathode.

Now we have to calculate the concentration of unknown Cd^{2+}.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Mg^{2+}]}{[Cd^{2+}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = emf of the cell = 1.80 V

E^o_{cell} = standard cell potential = 1.97 V

[Mg^{2+}] = concentration of magnesium ion = 1.00 M

[Cd^{2+}] = concentration of cadmium ion = ?

Now put all the given values in the above equation, we get

concentration of unknown Cd^{2+}.

1.80=1.97-\frac{0.0592}{2}\log \frac{(1.00)}{[Cd^{2+}]}

[Cd^{2+}]=1.807\times 10^{-6}M

Therefore, the concentration of unknown Cd^{2+} will be, 1.807\times 10^{-6}M

6 0
2 years ago
If the human body were a car, glucose would be:
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Aluminum oxide has a composition of 52.9% aluminum and 47.1% oxygen by mass. if 16.4 g of aluminum reacts with oxygen to form al
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Therefore, to completely react 16.4 grams of aluminum metal we need a minimum of 14.59 grams of oxygen gas.
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