Ask question

Ask question

All categories

2 years ago

9

The graph of the function f (x) = StartFraction 6 Over x minus 3 EndFraction is shown below. On a coordinate plane, a hyperbola

is shown. Both curves approach x = 3. What is the vertical asymptote of the function? x = –3 x = –2 x = 0 x = 3

1 answer:

myrzilka [38]2 years ago

5 0

Answer: x=3 or D on Edg.

Step-by-step explanation: I cheated on the quiz lol

You might be interested in

If p= (-2,7) find: Rx-axis(P)

Nana76 [90]

Answer:

P(-2,7)

P'(-2,-7), ANSWER

reflection across the x-axis rule:

(×,y) ===> (x,-y)

Easy way to do this is draw the point on graph paper and count the same units above/below the x-axis. This example you are 7 units above the x-axis so you would count 7 units below the x-axis giving you the point.

6 0

2 years ago

What is the domain and range of the function y = xn if n is an odd whole number? if n is an even whole number?

sergij07 [2.7K]

Answer:

Step-by What is the domain and range of the function y = xn if n is an odd whole number? if n is an even whole number?-step explanation:

8 0

2 years ago

Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when

valentina_108 [34]

Solution:

$f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$

We have to find the remainder when f(x) is divided by $x^2-1.$

x²-1=0

x= $\pm1$

$f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13$

So, remainder is 13 and -13.

5 0

1 year ago

Read 2 more answers

Lyle graphs triangle ABC on coordinate axes. He performs two transformations on this figure that result in the congruent triangl

Shtirlitz [24]

Answer:

a rotation 90˚ clockwise and then a reflection across the y-axis

Step-by-step explanation:

I'm doing the test right now

3 0

1 year ago

What is the factored form of a2 – 121?

Flura [38]

Answer:

The factored form $a^2-121$ is $(a+11)(a-11)$ .

Step-by-step explanation:

Given : $a^2-121$

We have to write the given expression in factored form.

Factor form of an expression is writing the expression in lower power form such that the product of factors given the original expression

Consider the given expression $a^2-121$ .

We know the algebraic identity $x^2-y^2=(x+y)(x-y)$

Here $a^2-121=a^2-(11)^2$ .

Comparing with identity stated above , we have x= a , b = 11 , thus, we get

$a^2-(11)^2=(a+11)(a-11)$ .

Thus, the factored form $a^2-121$ is $(a+11)(a-11)$ .

7 0

2 years ago