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lys-0071 [83]
2 years ago
3

If you are given a 2,900-gram sample of Hydrogen, and hydrogen has a half-life of 2,450 years. How much hydrogen is left after 1

9,600 years?
Chemistry
1 answer:
Kryger [21]2 years ago
3 0

Answer:

11.33g of hydrogen

Explanation:

We need to apply the formulae;

Nt/No= (1/2)^t/t1/2

Where;

Nt= mass of hydrogen remaining after a time t (the unknown)

No= mass of hydrogen initially present = 2900g

t= time taken for Nt mass of hydrogen to remain = 19600 years

t1/2= half-life of hydrogen= 2450 years

Substituting values;

Nt/2900= (1/2)^19600/2450

Nt/2900= (1/2)^8

Nt/2900= 1/256

256Nt= 2900

Nt= 2900/256

Nt= 11.33g of hydrogen

Therefore, 11.33g of hydrogen is left after 19600years.

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The volume of hcl gas required to react with excess ca to produce 11.4 l of hydrogen gas at 1.62 atm and 62.0 °c is ________ l.
seropon [69]

Answer:

22.8 L  

Step-by-step explanation:

We can use <em>Gay-Lussac's Law of Combining Volumes</em> to solve this problem:

Gases <em>at the same temperature and pressure</em> react in simple whole-number ratios.

1. Write the chemical equation.

Ratio:                 2 L                             1 L

          Ca(s) + 2HCl(g) ⟶ CaCl₂(s) + H₂(g)

V/L:                                                     11.4

2. Calculate the volume of HCl.

According to the law, 2 L of HCl form 1 L of H₂.

Then, the conversion factor is (2 L HCl/1 L H₂).

Volume of HCl = 11.4 L H₂ × (2 L HCl/1 L H₂)

                         = 22.8 L HCl

3 0
2 years ago
An electron is on a -2.5 eV energy level. The electron is struck by a 2.5 eV photon. What will most likely happen?
kati45 [8]
The correct answer would be C
5 0
2 years ago
During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
Brrunno [24]

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

3 0
2 years ago
The nitrogen content of organic compounds can be determined by the Dumas method. The compound in question is first reacted by pa
MAVERICK [17]

Answer:

Mass percent of nitrogen in the compound is 13,3%

Explanation:

Dumas method is an analytical method to determine nitrogen content in samples, thus:

CₐHₓNₙ + (2a+x/2) CuO  → aCO₂ +  ˣ/₂ H₂O +  ⁿ/₂ N₂ + (2a+x/2) Cu

As the CO₂ is removed with KOH, in the mixture you have H₂O and N₂

At 25°C. the vapor pressure of water is 23,8 torr, that means that the pressure due to N₂ is:

726torr - 23,8torr = 702,2 torr.

Using gas law:

n = PV/RT

Where:

P is pressure (702,2torr≡ 0,924 atm)

V is volume (0,0318L)

R is gas constant (0,082atmL/molK)

And T is temperature (25°C≡298,15K)

Replacing, number of moles of N₂, n, are:

n = 1,20x10⁻³moles of N₂. In grams:

1,20x10⁻³moles of N₂×\frac{28g}{1mol} =<em> 0,0336 g of N₂</em>.

Thus, mass percent of nitrogen in the compound is:

\frac{0,0336g N}{0,253gSample}×100= <em>13,3%</em>

<em></em>

I hope it helps!

7 0
2 years ago
In the human body hydrochloric acid is responsible for the low ph of the contents of the
natulia [17]
The wording makes this question difficult, but HCl is found in stomach acid. Hope this helps!
4 0
2 years ago
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