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chubhunter [2.5K]
2 years ago
7

There are 1800 students in a school. 53.5% of them are male. How many are female?

Mathematics
2 answers:
Ray Of Light [21]2 years ago
5 0

Answer:

Step-by-step explanation:

837 are females as 52.5 percent of 1800 equals 837.

Marizza181 [45]2 years ago
5 0

Answer:

Females = 100 - percent of males = 100 - 53.5 = 46.5%

Number of females = 46.5/100 × 1800 = 837

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How can we find how many inches wide the coat box is?
Alex777 [14]

Answer:

First we found the sum of 15.438 and 3.18. The subtract the answer from 32.476.

Option A is correct.

Step-by-step explanation:

The total width of box is = 32.476

Width of box of T-shirts = 15.438

Width of box of Socks = 3.18

We need to find width of coat box.

The width of coat box can be found as:

Total Width = Width of box of T-shirts + Width of box of Socks + width of coat box

32.476 = 15.438 + 3.18 + width of coat box

32.476 = 18.618 + width of coat box

width of coat box= 32.476 - 18.618

width of coat box = 13.858

So, The Width of coat box = 13.858 inches

First we found the sum of 15.438 and 3.18. The subtract the answer from 32.476.

Option A is correct.

5 0
2 years ago
The list shows the area in square feet of each apartment available for rent in a building. 565, 961, 867, 517, 627, 714, 517, 72
gladu [14]
STEP 1:
put numbers in order from lowest to highest
517, 517, 565, 627, 714, 728, 867, 961

STEP 2:
find the difference between the lowest and highest numbers

961 - 517= 444 ft^2 range

ANSWER: The range of the areas is 444 ft^2.

Hope this helps! :)
8 0
2 years ago
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At summer camp the ratio of boys to girls was 7:2 If there were 21 boys how many girls were there?
Alenkinab [10]
Ratio:\\7:2\\\\
7x-number\ of\ boys\\2x-number\ of\ boys\\\\
7x=21\ \ \ |:7\\
x=3\\\\
2x=2*3=6\\
Number\ of\ girls\ is\ equal\ to\ 6.
3 0
2 years ago
A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
2 years ago
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Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x? StartFraction 2 Over 11 EndFraction plus-or-minus
slamgirl [31]

Answer:

x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

11x^{2} -4x=1  

equate to zero

11x^{2} -4x-1=0  

so

a=11\\b=-4\\c=-1

substitute in the formula

x=\frac{-(-4)\pm\sqrt{-4^{2}-4(11)(-1)}} {2(11)}

x=\frac{4\pm\sqrt{60}} {22}

x=\frac{4\pm2\sqrt{15}} {22}

x=\frac{2\pm\sqrt{15}} {11}

x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}

therefore

StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction

7 0
2 years ago
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