All categories

2 years ago

6. A 2.2 kg rock rests on the edge of a bridge that is 3.3 m above a river. What is the

Physics

1 answer:

vovikov84 [41]2 years ago

6 0

Answer: 71 J

Explanation: The formula for gravitational potential energy is Epg= mgh.

So you plug in 2.2 as m, 3.3 as h and 9.81 as g. Once you do that you should get an answer of 71.2206. But because there are only two significant digits in the question, your answer must also have two significant digits.

You might be interested in

The rotational kinetic energy term is often called the kinetic energy in the center of mass, while the translational kinetic ene

weqwewe [10]

Answer:

Explanation:

The total kinetic energy is the sum of the kinetic energy in the center of mass (Rotational Kinetic energy) plus the kinetic energy of the center of mass( Translational Kinetic Energy).

The formula

$K_{tot} = K_{t} +K_{r}$ is applicable only when

The moment of inertia must be taken about an axis through the center of mass.

6 0

2 years ago

Read 2 more answers

The human head weighs 4.8 kg and its center of mas 1.8 cm in front of the spinal column joint. If the trapezius muscle inserts 1

Anarel [89]

Answer:

77.05N of force

Explanation:

Detailed explanation and calculation is shown in the image below

3 0

2 years ago

Read 2 more answers

Which of the following ways is usable energy lost?

tamaranim1 [39]

A. Friction or all of the above

4 0

2 years ago

Read 2 more answers

Consider a very small hole in the bottom of a tank 17.0 cm in diameter filled with water to a heightof 90.0 cm. Find the speed a

umka21 [38]

Answer:

Speed of water, v = 4.2 m/s

Explanation:

Given that,

Diameter of the tank, d = 17 cm

It is placed at a height of 90 cm, h = 0.9 m

We need to find the speed at which the water exits the tank through the hole. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

$v=\sqrt{2gh}$

$v=\sqrt{2\times 9.8\times 0.9}$

v = 4.2 m/s

So, the speed of water at which the water exits the tank through the hole is 4.2 m/s. Hence, this is the required solution.

5 0

2 years ago

A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act lik

Lady bird [3.3K]

Answer:

The options are approximations of the exact answers:

A) $1\times10^6N/C$

B) $2\times10^{-13}N$

C) $1\times10^{-2}V$

D) Toward the inner wall

E) $3\times10^{-17}J$

Explanation:

A) The electric field in a parallel plate capacitor is given by the formula $E=\frac{\sigma}{k\epsilon_0}$ , where $\epsilon_0=8.85\times10^{-12}C/Vm$ and in our case $\sigma=10^5C/m^2$ and, for air, $k=1.00059$ , so we have:

$E=\frac{10^5C/m^2}{(1.00059)(8.85\times10^{-12}C/Vm)}=1.13\times10^6N/C$

B) The K+ ion has one elemental charge excess, so its charge is $q=1.6\times10^{-19}C$ , and the force a charge experiments under an electric field E is given by F=qE, so we have:

$F=(1.6\times10^{-19}C)(1.13\times10^6N/C)=1.81\times10^{-13}N$

C) The potential difference between two points separated a distance d under an uniform electric potential E is given by $\Delta V=dE$ , so we have:

$\Delta V=(10\times10^{-9}m)(1.13\times10^6N/C)=1.13\times10^{-2}V$

D) The electic field goes from positive to negative charges, so it goes towards the inner wall.

E) The work done by an electric field through a potential difference $\Delta V$ on a charge Q is $W=Q\Delta V$ , and is equal to the kinetic energy imparted on it, so we have:

$K=(3\times10^{-15}C)(1.13\times10^{-2}V)=3.39\times10^{-17}J$

5 0

2 years ago