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Montano1993 [528]
2 years ago
10

Karen is making a set of costumes for the school play using a piece of cloth. She reduces the length of the cloth she intends to

use by 10%. If the initial length of the cloth that she wanted to use was 15 meters, what is the new length of the cloth she wants to use?
Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
6 0

Answer:

The new length is 13.5 meters

Step-by-step explanation:

Here, we are interested in calculating the new length of the cloth she wants to use

What we know from the question is that she is making a reduction of 10% from an initial of 15 meters

Thus, the length she is to use can be calculated by first getting what 10% of 15 meters is

Mathematically, that would be ;

10/100 * 15 = 1.5 meters

We now subtract this from the total of 15 meters

= 15 meters - 1.5 meters = 13.5 meters

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Solve x − 5y = 6 for x.
pentagon [3]

Answer:

All real numbers

Step-by-step explanation:

Solve a system of equations by elimination

With the equation given, you can solve for y to get: y = \frac{1}{5}x - \frac{6}{5}

Then, substitute this value in on the equation.

x - 5(\frac{1}{5}x - \frac{6}{5}) = 6

x - x + 6 = 6

6 = 6

The solution is all real numbers

8 0
2 years ago
I have a map where indy and ft. Wayne are 3 centimeters apart. Kokomo and indy are 1.5 cm apart on the map. If i know that indy
marta [7]

Indy and kokomo will be 60 miles apart in real life.

<u><em>Explanation</em></u>

On the map, Indy and ft. Wayne are 3 cm apart and Kokomo and Indy are 1.5 cm apart.

So, <u>the ratio </u>of the distance between Indy and ft. Wayne to the distance between Kokomo and Indy will be:  3: 1.5 = 30:15= 2:1

Now, lets assume that real distance between Indy and ft. Wayne is  2x cm and real distance between Kokomo and Indy is  x  cm.

Given that, the real distance between Indy and ft. Wayne is 120 miles.

That means....

2x= 120\\ \\ x= \frac{120}{2}=60

So, Indy and kokomo will be 60 miles apart in real life.

3 0
2 years ago
Galactic Rotation Speed. We are located about 27,000 light-years from the galactic center and we orbit the center about once eve
Alexxandr [17]

Answer:

speed = 796142.197 km/hr

Step-by-step explanation:

solution

we consider here orbit around galactic center is circular so

circumference formula will be here

circumference C = 2πr   ........1

here we know r = 27000

so

circumference C = 2 π × 27000

C = 169560 light year

so

we travel 169560 light year in 230000000 years

so distance will be

distance = \frac{169560}{230000000}

distance = 0.00073721 light year/year

and we know 1 year = 8760 hours

so 1 light year = 9.46027 ×10^{12} km

so

sped of moving is

speed = 0.00073721 × 9.46027 × \frac{10^{12}}{8760}  km/hr

speed = 796142.197 km/hr

5 0
2 years ago
A 16-ounce bottle of spring water is $1.76. A 20-ounce bottle of fresh water is $2.40. which statement about the unit prices is
faltersainse [42]

your answer is b spring water has a lower unit price of $0.12/ounce

8 0
2 years ago
Read 2 more answers
In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3


4 0
2 years ago
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