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IRISSAK [1]
2 years ago
12

You need to lower your debt to credit limit ratio by $1000. Your current limit is $1400. $1000 is what percent of your credit li

mit
Mathematics
1 answer:
malfutka [58]2 years ago
8 0
The answer is 85 there boio
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Mr Russo exchanged 200 euros for 270 dollars.how man dollars would he get for 300 euros
Nostrana [21]

200 euros       300 euros

--------------- = -----------------------------

270 dollars      x dollars

using cross products

200 * x = 270 * 300

divide each side by 200

x = 270 * 300/200

x =405 dollars

6 0
2 years ago
5/8 of the staff are male 5/12 of the staff works part time at the aquarium what is the fraction of the staff being female
Goryan [66]
I believe the answer is 3/8. The whole portion of employees, which is translated as 8/8 is deducted by 5/8, which is the population of male employees.
7 0
2 years ago
Read 2 more answers
A professor wants to determine information about the Internet usage of middle school students in one state. A sample of 500 boys
zlopas [31]
The answer is A because a sample of 500 boys and girls from middle schools across the state represents the population.
4 0
2 years ago
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Polygons ABCD and EFGH are similar. Find the length of EH?
3241004551 [841]

Most likely, polygon <span>ABCD</span> has sides of known lengths.
It is also likely that one of the sides of polygon <span>EFGH</span> (not <span>EH</span>) is also known. For instance, its side <span>EF</span>.

If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
<span>r=<span><span>EF</span><span>AB</span></span></span>

Since this ratio is constant for any two corresponding lengths,
<span>r=<span><span>EH</span><span>AD</span></span></span>

From the last two equations we can derive:
<span>EH=AD⋅<span><span>EF</span><span>AB</span></span></span>

Hope That Helped : ) (Took a minute)
5 0
2 years ago
The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de
ad-work [718]
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
z=\frac{173-154}{29}=0.655
Referring to a standard normal distribution table, and using z = 0.66, we find:
P(\bar x\ \textless \ 173)=0.7454
Therefore
P(\bar x\ \textgreater \ 173)=1-0.7454=0.2546
The answer is: 0.2546

4 0
2 years ago
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