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Goryan [66]
2 years ago
3

A 32.65-g sample of a solid is placed in a flask. Toluene, in which the solid is insoluble, is added to the fla sk so that the t

otal volume of solid and liquid together is 50.00 mL. The solid and toluene together weigh 58.58 g. The density of toluene at the temperature of the experiment is 0.864 g/ mL. What is the density of the solid?
Chemistry
1 answer:
iragen [17]2 years ago
4 0

Answer:

Density of the solid is 1.63g/mL

Explanation:

Hello,

Data;

Mass of solid = 32.65g

Mass of toluene = ?

Mass of solid + toluene = 58.58g

Density of toluene = 0.864g/mL

Mass of toluene = (mass of solid + toluene) - mass of solid

Mass of toluene = 58.58 - 32.65

Mass of toluene = 25.93g

But density = mass / volume

Density of toluene = mass of toluene / volume of toluene

Volume of toluene = mass of toluene / density of toluene

Volume of toluene = 25.93 / 0.864

Volume of toluene = 30.01mL

Volume of solid = total volume of the mixture (solid + toluene) - volume of toluene

Volume of solid = 50 - 30.01

Volume of solid = 19.99mL

Density of the solid = mass of solid / volume of solid

Density of the solid = 32.65 / 19.99

Density of the solid = 1.63g/mL

Therefore the density of the solid is 1.63g/mL

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Silver nitrate and aluminum chloride react with each other by exchanging anions: 3agno3 (aq) + alcl3 (aq) → al(no3)3 (aq) + 3agcl (s) what mass in grams of agcl is produced when 4.22 g of agno3 react with 7.73 g of alcl3?
5 0
2 years ago
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Acetone major species present when dissolved in water
jek_recluse [69]

Answer: acetone molecule ( CH₃-CO-CH₃)


Explanation:


1) Acetone is CH₃-CO-CH₃


2) That is a molecule (build up of covalent bonds).


3) When dissolved, covalent bonded compounds remain as separate molecules, then it is said that the major species present in the solution is the molecule. The molecules of acetone are surrounded (sovated) by the molecules of water.


This as opposed to the case of ionic compounds that ionize. When a compound as NaCl dissolves in water, it ionizes completely, so the major speceies are not NaCl formulas, but the ions Na⁺ and Cl⁻, not molecules.


That leads to the answer: the major species present when acetone is dissolved in water is the molecules of acetone (you do not need to state the fact that the molecules of water are part of the solution, because that is not the target of the question).



3 0
2 years ago
What is the mass of 2.5 moles of hydrogen fluoride gas HF
Nady [450]

Answer:

You will get 5.0 g of hydrogen.

Explanation:

As with any stoichiometry problem, we start with the balanced equation.

Sn

l

+

2HF

→

SnF

2

+

H

2

Moles of H

2

=

2.5

mol Sn

×

1 mol H

2

1

mol Sn

=

2.5 mol H

2

Mass of H

2

=

2.5

mol H

2

×

2.016 g H

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1

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=

5.0 g H

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7 0
2 years ago
PLS HELP! 50 PTS!
ioda

Answer:

The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.

Explanation:

<em>The correct option would be that the average kinetic energy of the gas particles is greater in container B because it has a higher temperature.</em>

<u>According to the kinetic theory of matter, the temperate of a substance is a measure of the average kinetic energy of the molecules of substance. In other words, the higher the temperature of a substance, the higher the average kinetic energy of the molecules of the substance.</u>

In the illustration, the gas in container B showed a higher temperature than that of container A as indicated on the thermometer, it thus means that the average kinetic energy of the molecules of gas B is higher than those of gas A.

5 0
2 years ago
A 0.529-g sample of gas occupies 125 ml at 60. cm of hg and 25°c. what is the molar mass of the gas?
Llana [10]

<span>Let's </span>assume that the gas has ideal gas behavior. <span>
Then we can use ideal gas formula,
PV = nRT<span>

</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
<span>
</span>P = 60 cm Hg = 79993.4 Pa
V = </span>125  mL = 125 x 10⁻⁶ m³

n = ?

<span> R = 8.314 J mol</span>⁻¹ K⁻¹<span>
T = 25 °C = 298 K
<span>
By substitution,
</span></span>79993.4 Pa<span> x </span>125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 298 K<span>
                                          n = 4.0359 x 10</span>⁻³ mol

<span>
Hence, moles of the gas</span> = 4.0359 x 10⁻³ mol<span>

Moles = mass / molar mass

</span>Mass of the gas  = 0.529 g 

<span>Molar mass of the gas</span> = mass / number of moles<span>
                                    = </span>0.529 g / 4.0359 x 10⁻³ mol<span>
<span>                                    = </span>131.07 g mol</span>⁻¹<span>

Hence, the molar mass of the given gas is </span>131.07 g mol⁻¹

4 0
2 years ago
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