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musickatia [10]
2 years ago
6

The density of methanol is 0.7918g/mL. Calculate the mass of 89.9mL of this liquid.

Chemistry
1 answer:
Novosadov [1.4K]2 years ago
4 0
The mass is 71.2 g.

Mass = 89.9 mL × \frac{0.7918 g}{1 mL} = 71.2 g
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What is the density of 96 ml of a liquid that has a mass of 90.5 g?
Otrada [13]

Answer:

Density = Mass / Volume.   so,  x = 90.5 g / 96 mL ... The Density would be 0.942 g/mL

8 0
2 years ago
Complete the sentence. When an acid is added to water, hydroxide ions __________.
kenny6666 [7]

Answer:

The hydroxide ions decrease.

Explanation:

I got it right on the quiz. This is what I saw. Read this, "Adding water to an acid or base will change its pH. Water is mostly water molecules so adding water to an acid or base reduces the concentration of ions in the solution. When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7."

Hope this helps! Tell me if this is wrong just incase.

8 0
2 years ago
Read 2 more answers
500ml of a buffer solution contains 0.050 mol nahso3 and 0.031
nydimaria [60]

Answer:

The answers are explained below

Explanation:

a)

Given: concentration of salt/base = 0.031

concentration of acid = 0.050

we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.031/0.050) = 1.59

b)

we have HSO₃⁻ + OH⁻ ------> SO₃²⁻ + H₂O

Moles i............0.05...................0.01.................0.031.....................0

Moles r...........-0.01.................-0.01................0.01........................0.01

moles f...........0.04....................0....................0.041.....................0.01

c)

we will use the first equation but substituting concentration of base as 0.031 + 10ml = 0.031 + 0.010 = 0.041

Hence, we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.041/0.050) = 1.71

d)

pOH = -log (0.01/0.510) = 1.71

pH = 14 - 1.71 = 12.29

e)

Because the buffer solution (NaHSO3-Na2SO3) can regulate pH changes. when a buffer is added to water, the first change that occurs is that the water pH becomes constant. Thus, acids or bases (alkali = bases) Additional may not have any effect on the water, as this always will stabilize immediately.

4 0
2 years ago
How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?
Shtirlitz [24]
I think you means the KO2 reacts with H2O. The equation of this reaction is 4KO2+2H2O->4KOH +3O2. The ratio of mole number of O2 and KO2 is 3:4. So the mole number of O2 produced is 0.500/4*3=0.375 mol.
6 0
2 years ago
Which diagram shows a pattern similar to the emission spectrum of hydrogen?
rosijanka [135]
Hello!

the correct answer would be b!

explanation: with increasing wavelength, it goes from higher energy to lower energy. since energy levels converge at higher energy levels, the answer b shows that the image of line becoming more separated than the following other answers

if this helps, click “thanks” :)

- emily
3 0
2 years ago
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