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masya89 [10]
2 years ago
9

Select the atoms or ions drawn with valid Lewis dot structures. A) A carbon has a dot on top, right, bottom and to the left.a ni

trogen has one dot on top, left and to the bottom and has a charge of minus 3.a nitrogen has a dot on top, right, bottom and to the left. B) An oxygen has two dots on top and bottom and one dot to the left and to the right. C) A carbon has two dots on top, right, bottom and to the left and a charge of plus four. D) An oxygen has two dots on top, left and to the bottom and a charge of minus 2.
Chemistry
1 answer:
charle [14.2K]2 years ago
6 0

Answer:

B, C

Explanation:

The atoms or ions with the valid Lewis dot structures are B and C.

In A;

The Lewis structure of the carbon is correct. Each of the four dots represent the four valence electrons.

The  nitrogen with one dot on top, left and to the bottom and has a charge of minus 3 is wrong. For it to have a charge of -3 it must have 8 lewis dots ( two on the top, right, bottom and to the left)

The nitrogen with four dots (on top, right, bottom and to the left) is wrong.

In B;

An oxygen has two dots on top and bottom and one dot to the left and to the right. This is correct , the 6 dots represent the valence electrons of oxygen.

In C;

A carbon has two dots on top, right, bottom and to the left and a charge of plus four. This is correct because the charge indicates that it has gained four extra electrons so its valence electrons is now 8.

In D;

An oxygen has two dots on top, left and to the bottom and a charge of minus 2. This is wrong because the lewis dots are incomplete. Two dots are missing.

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100. cal of heat are added to 18.0 g of ethanol (0.581 cal/g °C) originally at 23 °C. The final temperature is ____________.
uranmaximum [27]

Answer:

Final temperature is 32.56 °C

Explanation:

The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1°C.

The following equation/formula is used;

Q = m × c × ΔT

Where; Q= amount of heat supplied

(cal)

M= mass of ethanol (g)

C= specific heat of ethanol

(cal/g °C)

ΔT= change in temperature (°C)

i.e. (final temperature - initial

temperature)

According to the question, Q= 100 calories (cal), M= 18g, C= 0.581 cal/g °C, initial temperature = 23°C, final temperature = ?

Hence, we insert our values into the equation;

Q = m × c × ΔT

ΔT = Q/mc

(Final T - Initial T) = Q/mc

(Final T - 23) = 100/ 18 × 0.581

(Final T - 23) = 100/10.458

Final T - 23 = 9.562

Final T = 23 + 9.562

Final T = 32.562

Hence, the final temperature of ethanol is 32.56°C

4 0
2 years ago
Sea arches and sea stacks provide evidence of weathering and erosion. In three to five sentences, explain the roles weathering a
Montano1993 [528]

Answer:

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Explanation:

4 0
2 years ago
The four rows of data below show the boiling points for a solution with no solute, sucrose (C12H22O11), sodium chloride (NaCl),
skad [1K]
The following are the answers to the different questions: 
<span>The four rows of data below show the boiling points for a solution with no solute, sucrose (C12H22O11), sodium chloride (NaCl), and calcium chloride (CaCl2) (not in that order). Which boiling point corresponds to calcium chloride?

A. 101.53° C

Which of the following solutions will have the lowest freezing point?

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4 0
2 years ago
Read 2 more answers
Based on the products obtained, rank the functional groups (acetamido, amino, and methoxy) in order of increasing ability to act
I am Lyosha [343]

Answer:

Amino >Methoxy > Acetamido

Explanation:

Bromination is of aromatic ring is an electrophilic substitution reaction. The attached functional group to the benzene ring activates or deactivate the aromatic ring towards electrophilic substitution reaction.

The functional group which donates electron to the benzene ring through inductive effect or resonance effect activates the ring towards electrophilic substitution reaction.

The functional group which withdraws electron to the benzene ring through inductive effect or resonance effect deactivates the ring towards electrophilic substitution reaction.

Among given, methoxy and amino are electron donating group. Amino group are stronger electron donating group than methoxy group. Acetamido group because of presence of carbonyl group becomes electron withdrawing group.

Therefore, decreasing order will be as follows:

Amino >Methoxy > Acetamido

7 0
2 years ago
If you were to assume a 95% yield for the formation of the phosphonium ion, how many milligrams of benzyl chloride and triphenyl
luda_lava [24]
I am attempting the problem for phosphonium Ion rather than its chloride salt. The chemical equation is shown below along with molar masses in mg.

First of all we will calculate the amounts of reactants required for the synthesis of 220 mg of phophonium ion. Calculations for both reactants is as follow,

For Benzyl chloride,
\frac{353420 mg of Phosphonium is formed by reacting}{220 mg of Phosphonium will be formed by} = \frac{126580 g of benzyl chloride}{X}

Solving for X,
X = \frac{220 mg . 126580 mg}{353420 mg}
X = 78.79 mg

For PPh₃:
\frac{353420 mg of Phosphonium is formed by reacting}{220 mg of Phosphonium will be formed by} = \frac{262290 g of PPh3}{X}

Solving for X,
X = \frac{220 mg . 262290 mg}{353420 mg}
X = 163.27 mg

Now
, Assuming these values as for 95 % conversion, we can calculate 100 % yield as follow,

when   \frac{95 percent}{100 percent} = \frac{220 g}{X}
Solving for X,

X = \frac{220 . 100}{95} = 231.57 mg

Now, calculate reactants mass with respect to 231.57 mg
when  \frac{220 mg phosphonium required}{231.57 mg require} = \frac{78.79 g of benzyl chloride}{X}
Solving for ,

X = \frac{231.57 . 78.79}{220} = 82.93 mg of Benzyl chloride

when  \frac{220 mg phosphonium required}{231.57 mg require} = \frac{163.27 g of PPh3}{X}
Solving for ,

X = \frac{231.57 . 163.27}{220} = 171.85 mg of PPh3

So,
reaction was started with reacting 82.93 mg of Benzyl Chloride and 171.85 mg of Triphenyl Phosphine.
7 0
2 years ago
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