Two figures are similar if one is the scaled version of the other.
This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.
To be more precise, you only need two steps to prove that every two circles are similar:
- Translate one of the two circles so that they have the same center
- Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well
Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.
Recapping, we have:
- Start with circle X and radius r
- Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
- Scale the radius of circle X' until it becomes
. This new circle, say X'', is similar to X' because you only scaled it
So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.
Answer:
It is proved that 
exixts at (0,0) but not differentiable there.
Step-by-step explanation:
Given function is,
- To show exixtance of
we take,
exists.
And,
exists.
- To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,
where m is a variable.
which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).
Hi there Mary Dominguez, So what a vertical line test down is to find out if a particular graph is a function or not. What you do is take a vertical strait line and move it right to left or left to right, depending on your preference, along the X axis. The reason this works is a function can not have an x that has 2 different y values. If we use the vertical line test on a graph with say a graph that has (2,3) and (2,4) we can use the vertical line test and see that the line hits 2 points at once which means its not a function :)
Answer:
f(x) = 500(2)^x
Step-by-step explanation:
Let's assume the initial x value is 0
500(0)^2 = 0
100(0)^5 = 0
500(2)^0 = 500
500(0)^2 = 0
