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Trava [24]
2 years ago
10

Mateo has already swam 4/5 of the 2000 meters he is swimming today. If he continues swimming at a pace of 3/4 of a meter per sec

ond, which expression shows the amount of time it will take him to swim the remaining distance. A) 2000 × 4/5 × 3/4. B) 2000 × 1/5 × 3/4. C) 2000 × 1/5 ÷ 3/4 ​
Mathematics
2 answers:
Vinvika [58]2 years ago
7 0

Answer: C)

Step-by-step explanation: By multiplying 2000 for 1/5, you discover the remaining distance. Considering Mateo swim 3/4 meters per second, dividing the first result for 3/4 will give you the amount of time that he will take to swim what's left (in units of <em>seconds)</em>

olga nikolaevna [1]2 years ago
3 0

Answer:

Its D 2000 x 1/5 divided by 3/4

Step-by-step explanation:

Got it right on review

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The rabbit population in a certain area is 500​% of last​ year's population. There are 1,100 rabbits this year. How many were th
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Answer:

5,500 rabbits

Step-by-step explanation:

500% of something is 5 times the original amount. 1,100 rabbits times 5 equals 5,500.

8 0
2 years ago
A lake near the Arctic Circle is covered by a sheet of ice during the cold winter months. When spring arrives, the ice starts to
hichkok12 [17]

Answer: 1.5 meters


Step-by-step explanation:

Given: A lake near the Arctic Circle is covered by a sheet of ice during the cold winter months. S

S(t) models the ice sheet's thickness (in meters) as a function of time t (in weeks) S(t)=-0.25t+4

if we put x=0, then

S(0)=-0.25(0)+4\\=4\ meters

So 4 meters is the initial thickness

To find the thickness after 6 weeks, put x=6 we get

S(6)=-0.25(6)+4\\=-1.5+4=2.5\ meters

Decrease in thickness every 6 weeks= 4-2.5=1.5\ meters


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2 years ago
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marcus can buy 0.3 pound of sliced meat from a deli for $3.15 how much will 0.7 pound of sliced meat cost?
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$22.05 because $3.15 times 0.7 is= 22.05
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Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its
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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
2 years ago
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