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Scorpion4ik [409]
2 years ago
10

What is the decimal multiplier to decrease by 7.4%?

Mathematics
1 answer:
RUDIKE [14]2 years ago
6 0

Answer:

0.99926

Step-by-step explanation:

Let the original number be 100, to decrease it by 7.4%, let's convert 7.4% to a decimal point. 7.4% = 0.074

100-0.074 = 99.926

Therefore the decimal multiplier to decrease by 7.4% is multiplying the original number by 99.926/100 = 0.99926

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The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inche
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70 inches. The answer is e. 70 inches.
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2 years ago
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A study was conducted on the effects of long-term marriage (more than 10 years). Researchers gathered data from a random sample
True [87]

Answer:

The correct option is;

We cannot infer a cause and effect relationship because the multiple variables were included

Step-by-step explanation:

The criteria required in order to establish a cause and effect relationship includes the following;

1) There must be a temporal precedence between the cause and the effect such that the cause must take place before the effect

In the question, it is not clearly stated weather there was a divorce (the likely cause) takes place before the event

2) In the vent that the cause occurs, the effect must occur

Therefore, all those who are not married are expected to be deceased for there to be a cause and effect relationship

3) The cause and effect relationship must not be explicable by other factors

In the question, it is stated that those who were married were more likely to be active physically, maintain an healthy weight and were nonsmokers, which are factors that contribute to longevity.

8 0
2 years ago
Rewrite each statement using the appropriate mathematical language 1. There exists a number b belonging to the set B 2. Even num
Shtirlitz [24]

Answer:

1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻

Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

N ⊂ Z ⊂ Q ⊂ R .

4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write

J ≤ J⁻¹ : J ∈ Z⁻

4 0
2 years ago
In a class Vidya ranks 7th from the top. Divya
liq [111]

Answer:

52 students

Step-by-step explanation:

From the question above, we have the following information:

a) Vidya ranks 7th from the top.

Mathematically,

Vidya = 7th student

b) Divya 3 ranks behind Vidya.

Divya = Vidya + 3

Hence, Mathematically:

Divya = 7 + 3 = 10

Divya = 10th student

c) Also, Divya is 7 ranks ahead of Medha.

Mathematically,

Medha = 10 + 7= 17

Medha= 17th student

d)Sushma is 32 ranks behind Medha

Mathematically,

Sushma = Medha + 32

= 17 + 32 = 49

Sushma is the 49th student

Therefore, since, Sushma is 4th from the bottom, total number of students is:

49 + 3 = 52 students

5 0
2 years ago
Select all polynomials that are divisible by (x-1)(x−1)left parenthesis, x, minus, 1, right parenthesis. Choose all answers that
alexdok [17]

Answer:

Step-by-step explanation:

For us to be able to determine the polynomials that are divisible by (x-1), this means that x-1 must be a factor for the functon to be able to divide any of the polynimial.

Since x-1 is a factor, we can get the value of x

x-1 = 0

x =0+1

x = 1

Next is for to substitute x - 1 into the polynomial and see the ones that will give us zero

For A(x)=3x^3+2x^2-x

A(1) = 3(1)^3+2(1)^2-(1)

A(1) = 3+2-(1)

A(1) = 5-1

A(1) = 4

Since A(1) ≠ 0, then x-1 is not divisible by the polynomial function.

<u>For B(x)=5x^3-4x^2-x</u>

B(1)=5(1)^3-4(1)^2-1

B(1)=5-4-1

B(1)=1-1 = 0

Since B(1) = 0, hence x-1 is divisible by 5x^3-4x^2-x

For the polynomial  C(x)= 2x^3-3x^2+2x-1

C(1)=2(1)^3-3(1)^2+2(1)-1

C(1)=2-3+2-1

C(1)= -1+1

C(1)= 0

Since C(1) = 0, hence x-1 is divisible by<u> the </u>

<u />

<u>F</u>or the polynomial D(x)=x^3+2x^2+3x+2

D(1)=1^3+2(1)^2+3(1)+2

D(1)=1+2+3+2

D(x) = 8

Hence the polynomial D(x) is not divisible by x-1

Hence the correct options are B(x)=5x^3-4x^2-x and 2x^3-3x^2+2x-1

8 0
2 years ago
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