Question

PLEASE HELP ASAP!!! Next, the team wants to explore how it can change the steepness of the curved pit. Identify how the graph of each equation compares with the graph of the parent quadratic equation, y = x2. Drag the equations to the correct location on the chart. Not all equations will be used.

Answer 1

Answer:

More steeper → y = 2x², y = (2x)²

Less steeper → $y=\frac{1}{2}x^2$, $y=(\frac{1}{2}x)^2$

Step-by-step explanation:

Parent quadratic equation has been given as,

y = x²

Coefficient of x² defines the nature of the graph in terms of stretch,

1).If the coefficient of x² is greater than 1 then the parent equation will be vertically stretched and will be more steeper.

2). If the coefficient is between 0 and 1, graph of the parent function will be vertically compressed and will be less steeper.

3). If a is negative, graph will be reflected across the x-axis.

From the given options,

Curves more steeper than y = x²,

y = 2x², y = (2x)²

Curves less steeper than y = x²,

$y=\frac{1}{2}x^2$ , $y=(\frac{1}{2}x)^2$

Curve y = -x² is the reflected form of parent function y = x²