answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AveGali [126]
2 years ago
3

In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to

the top of the slope, a rider and his tube, with a total mass of 88 kgkg , are pulled at a constant speed by a tow rope that maintains a constant tension of 350 NN .
How much thermal energy is created in the slope and the tube during the ascent of a 30-m-high, 120-m-long slope?
Physics
1 answer:
Licemer1 [7]2 years ago
8 0

Answer:

16.10 kJ

Explanation:

The thermal energy created in the slope can be found by definition of work (W):  

W = E_{f} - E_{i} = K_{f} + P_{f} + Th_{f} - (K_{i} + Th_{i})

<u>Where</u>:

K_{f} and K_{i}: is the final and initial kinetic energy

P_{f}: is the final potential energy

Th_{f} and Th_{i}: is the final and initial thermal energy

W = \frac{1}{2}mv_{f}^{2} + mgh - \frac{1}{2}mv_{i}^{2} + Th_{f} - Th_{i}

We have that W is:

W = F*d = T*d

<u>Where</u>:

F: is the force equal to the tension (T)

d: is the displacement = 120 m

And since the speed is constant, v_{i} = v_{f} we have:

T*d = mgh + \Delta Th

\Delta Th = T*d - mgh = 350 N*120 m - 88 kg*9.81 m/s^{2}*30 m = 16101.6 J

Therefore, the thermal energy created in the slope and the tube during the ascent is 16.10 kJ.

I hope it helps you!  

You might be interested in
A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average
frez [133]
 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
</span>
<span>0 = 20 + a(4) 

</span><span>4 x a = -20 
</span>
so, the answer is <span>-5 m/s^2. or -5 meter per second</span>
8 0
2 years ago
Read 2 more answers
A series of waves with decreasing wavelength labeled radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, gamm
kotegsom [21]

Answer:

label A= radio waves, label C= infrared, Label D= visible Light, Label G= gamma rays.

Explanation:

hope it helped??

can i have a thanks, a 5 star, and a brainliest please

can we be friends  

6 0
2 years ago
Read 2 more answers
a partially inflated weather balloon has a volume of 1.56 * 10^3 L and a pressure of 98.9 lPa. What is the volume of the balloon
e-lub [12.9K]
To solve the problem, we enumerate all the given first. Then the required and lastly the solution.

Given:

V1= 1.56x10^3 L = 1560 L                P2 = 44.1 kPa
P1 = 98.9 kPa

Required:  V2

Solution:

Assuming the gas is ideal. Ideal gas follows Boyle's Law which states that at a given temperature the product of pressure and volume of a gas is constant. In equation,

PV = k

Applying to the problem, we have
 
P1*V1 = P2*V2
(98.9 kPa)*(1560 L) = (44.1 kPa)*V2
V2 = 3498.5 L

<em>ANSWER: V2 = 3498.5 L</em>
7 0
2 years ago
Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m
netineya [11]

Answer: m \frac{d}{dt}v_{(t)}

Explanation:

In the image  attached with this answer are shown the given options from which only one is correct.

The correct expression is:

m \frac{d}{dt}v_{(t)}

Because, if we derive velocity v_{t} with respect to time t we will have acceleration a, hence:

m \frac{d}{dt}v_{(t)}=m.a

Where m is the mass with units of kilograms (kg) and a with units of meter per square seconds \frac{m}{s}^{2}, having as a result kg\frac{m}{s}^{2}

The other expressions are incorrect, let’s prove it:

\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)} This result has units of kg\frac{m}{s}

m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m This result has units of kg

m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C This result has units of kgm^{2} and C is a constant

m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m This result has units of kg

m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m This result has units of kg

\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C This result has units of kg \frac{m^{3}}{s^{3}} and C is a constant

m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{4}} and C is a constant

\frac{m}{2} \frac{d}{dt}{(v_{(x)})}^{2}=0 because v_{(x)} is a constant in this derivation respect to t

m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{2}} and C is a constant

6 0
2 years ago
An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It start
FrozenT [24]

Answer:

  • The total distance traveled is 28 inches.
  • The displacement is 2 inches to the east.

Explanation:

Lets put a frame of reference in the problem. Starting the frame of reference at the point with the 0-inch mark, and making the unit vector \hat{i} pointing in the west direction, the ant start at position

\vec{r}_0 = 16 \ inch \ \hat{i}

Then, moves to

\vec{r}_1 = 29 \ inch \ \hat{i}

so, the distance traveled here is

d_1 = |\vec{r}_1 - \vec{r}_0  | = | 29 \ inch   \ \hat{i} - 16 \ inch   \ \hat{i}  |

d_1 =  | 13 \ inch   \ \hat{i}  |

d_1 =  13 \ inch

after this, the ant travels to

\vec{r}_2 = 14 \ inch \ \hat{i}

so, the distance traveled here is

d_2 = |\vec{r}_2 - \vec{r}_1  | = | 14 \ inch   \ \hat{i} - 29 \ inch   \ \hat{i}  |

d_2 =  | - 15 \ inch   \ \hat{i}  |

d_2 =  15 \ inch

The total distance traveled will be:

d_1 + d_2 = 13 \ inch + 15 \ inch = 28 \ inch

The displacement is the final position vector minus the initial position vector:

\vec{D}=\vec{r}_2 - \vec{r}_1

\vec{D}= 14 \ inch   \ \hat{i} - 16 \ inch \ \hat{i}

\vec{D}= - 2 \ inch \ \hat{i}

This is 2 inches to the east.

6 0
2 years ago
Other questions:
  • Alyssa is carrying a water balloon while running down a field at a speed of 14 m/s. She tosses the water balloon forward toward
    9·2 answers
  • The drag force, fd, imposed by the surrounding air on a vehicle moving with velocity v is given by fd = cdaρv 2/2 where cd is a
    7·1 answer
  • A policeman starts giving chase 60 seconds after a stolen car zooms by at 108 km/hr. At what minimum speed should he drive if he
    12·1 answer
  • A particle decelerates uniformly from a speed of 30 cm/s to rest in a time interval of 5.0 s. It then has a uniform acceleration
    10·1 answer
  • A herringbone or tire track pattern on a radiograph is a result of: _______.A. Insufficient vertical angulation B. Film bending
    5·1 answer
  • Stella is driving down a steep hill. She should keep her car __________ to help _________. a. light, it speed up in a higher b.
    14·2 answers
  • Q9: Suppose that the metal cylinder in the last problem has a mass of 0.10 kg and the coefficient of static friction between the
    8·1 answer
  • In order to hike around a portion of Lake Allatoona, a tour guide determines that he must take his group 150 m east, 60 m north,
    8·1 answer
  • Which of the following is the BEST example of increasing the intensity of a workout? A. running one mile further than normal B.
    11·2 answers
  • Write the equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!