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horrorfan [7]
2 years ago
7

Bill buys and sells laptops. Last month Bill bought 50 laptops. He paid £400 for each laptop. He sold 40 of these laptops at a p

rofit of 30% on each laptop and 10 of these laptops at a profit of 15% on each laptop. Bill’s target last month was to sell all 50 laptops for a total of at least £25 000. Did Bill reach this target?
Mathematics
1 answer:
Ivenika [448]2 years ago
6 0

Answer:

As Bill's sales is £25400, which is greater than £25000, he achieved his target.

Step-by-step explanation:

Cost of each laptop = £400

lets calculate for 40 laptops first

Given, he sold 40 of these at 30% profit

30% of cost price = 30% of  £400  = 30/100 * 400 = 120

Therefore, selling price of these laptops =  £400  +  £120 =  £520

Total sales generated from selling 40 of these laptop = 40*£520

= £520 =£20,800  

lets calculate for 10 laptops now

Given, he sold 10 of these at 15% profit

15% of cost price = 15% of  £400  = 15/100 * 400 = 60

Therefore, selling price of these laptops =  £400  +  £60 =  £460

Total sales generated from selling 10 of these laptop = 10*£460

= £4600

Total sales generated from selling all the 50 laptop =  

Total sales generated from selling 40 of these laptop + Total, sales generated from selling 10 of these laptop = £20,800  + £4600 = £25,400

Target for Bill = £25000

As his sales is £25400, which is greater than £25000, he achieved his target.

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Suppose you have 20 coins that total $3.00. Some coins are nickels and some are quarters. Which of the following pairs of equati
shusha [124]

Answer: D. n + q = 20

5n + 25q = 300

Step-by-step explanation:

Let n represent the number of nickels that you have.

Let q represent the number of quarters that you have.

Suppose you have 20 coins. It means that

n + q = 20

The total value of the coins is $3. The value of a quarter is $0.25 and the value if a nickel is $0.05. Therefore, the equation would be

0.05n + 0.25q = 3

Multiplying both sides of the equation by 100, it becomes

5n + 25q = 300

The correct option is

D. n + q = 20

5n + 25q = 300

6 0
1 year ago
A building has an entry the shape of a parabolic arch 74 ft high and 28 ft wide at the base as shown below.
sergiy2304 [10]
The equation of a parabola with vertex at (h,k) is 
y=a(x-h)²+k

vertex isi at (0,0)

y=a(x-0)²+0
y=a(x)²
y=ax²
find a

we see that one point is (14,-74)
x=14 and y=-74

-74=a(14²)
-74=196a
divide both sides by 196
-37/98=a

the equation is 

y= \frac{-37}{98} x^2




6 0
2 years ago
Read 2 more answers
What is the circumference of a circle with a diameter of 45 centimeters?
zysi [14]
It is 141.4 centimetres. This is because the circumference is obtained by multiplying pi with the diameter.
3 0
1 year ago
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Please... Solve this: the bearing of a tree from a house is 295°. Find the bearing of the house from the tree.
jonny [76]

Given parameters:

Bearing of the tree from the house  = 295°

Unknown:

Bearing of the house from the tree = ?

Solution:

This is whole circle bearing problem(wcb). There are different ways of representing directions from one place to another. In whole circle bearing, the value of the bearing varies from 0° to 360° in the clockwise direction.

To find the back bearing in this regard, simple deduct the forward bearing from 360°;

    Backward bearing  = 360° -295°

                                    = 65°

The bearing from house to the tree is 65°

4 0
1 year ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) P(X \leq 8) = 0.932 (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032 (cumulative)

(d) P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 (cumulative)

(e) P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251

5 0
2 years ago
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