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Simora [160]
2 years ago
4

A biker’s speed is 1.5 times faster than a walker’s. They started simultaneously from the same point and in 1.5 hours the distan

ce between them was 12.5 miles. What are their speeds, depending on whether they walked in the same or opposite directions?
Mathematics
1 answer:
photoshop1234 [79]2 years ago
5 0
Let x=walker's speed

1.5x=biker's speed

1.5x-x=.5x=speed by which distance is formed

between biker and walker.

speed=distance/travel time

.5x=12.5/1.5

x=16 2/3

1.5x=25

walker's speed=16 2/3 mph

biker's speed=25 mph
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the length of the rectangle is measured as 370mm correct to 2 significant figures.a) what is the upper bound for the length?the
ivanzaharov [21]

Answer:

a) 375

b) 7062.75 mm²

Step-by-step explanation:

b) We need to find the shortest possible width and length to get the smallest possible area.

To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.

The boundaries are, therefore: 19.35 - 19.45

As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.

And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:

365 * 19.35 = 7062.75 mm²

7 0
1 year ago
Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average
lutik1710 [3]
Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5

Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.
4 0
2 years ago
Read 2 more answers
If angle ABC is one degree less than three times angle ABD and angle DBC=47 find each measure
Contact [7]

It has not been indicated whether the figure in the questions is a triangle or a quadrilateral. Irrespective of the shape, this can be solved. The two possible shapes and angles have been indicated in the attached image.

Now, from the information given we can infer that there is a line BD that cuts angle ABC in two parts: angle ABD and angle DBC

⇒ Angle ABC = Angle ABD + Angle DBC

Also, we know that angle ABC is 1 degree less than 3 times the angle ABD, and that angle DBC is 47 degree

Let angle ABD be x

⇒ Angle ABC = 3x-1

Also, Angle ABC = Angle ABD + Angle DBC

Substituting the values in the above equations

⇒ 3x-1 = x+47

⇒ 2x = 48

⇒ x = 24

So angle ABD = 24 degree, and angle ABC = 3(24)-1 = 71-1 = 71 degree

8 0
2 years ago
water will be both added to and drained from a bathtub at the same time for 5 minutes. the total amount of water added to the ba
Leto [7]
There would be 12 litres in the tub after 4 minutes
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2 years ago
URGENT!! Please help Find the values of y=c(x) 3 square x, for x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, , 0.729 a
mojhsa [17]

Answer:

We have

$y=c(x)=\sqrt[3]{x} $

\text{for } x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729 \text{ and } 1

We have 10 points to find:

\text{Point A}(0, 0)

\text{Point B}(0.008, 0.2)

\text{Point C}(0.027, 0.3)

\text{Point D}(0.064, 0.4)

\text{Point E}(0.125, 0.5)

\text{Point F}(0.216, 0.6)

\text{Point G}(0.343, 0.7)

\text{Point H}(0.512, 0.8)

\text{Point I}(0.729, 0.9)

\text{Point J}(1, 1)

4 0
2 years ago
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