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romanna [79]
2 years ago
15

For the mineral torbernite, Cu(UO2)2(PO4)2⋅8H2O, determine the ratio, by number, of H atoms to O atoms

Chemistry
2 answers:
vredina [299]2 years ago
7 0

Answer:

The ratio by number of H atoms to O atoms is: 4:5

Explanation:

The mineral torbernite, : Cu(UO_2)_2(PO_4)2⋅8H_2O

Number of oxygen atoms in the mineral :

=2\times 2+4\times 2+8\times 1=20

Number of hydrogen atoms in the mineral :

=8\times 2=16

The ratio by number of H atoms to O atoms is:

\frac{16}{20}=\frac{4}{5}=4:5

astra-53 [7]2 years ago
4 0
H:O = 4:5; (UO₂)₂ = 4 O atoms; (PO₄)₂ = 8 O atoms: 8H₂O = 16 H atoms + 8 O atoms; Total = 16 H atoms + 20 O atoms; H:O = 16:20 = 4:5
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For a pure substance, the liquid and gaseous phases can only coexist for a single value of the pressure at a given temperature.
anastassius [24]

Answer:

No, it is not.

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2 years ago
Determine the transition length at the entrance to a 10 mm tube through which 100 percent glycerol at 60 C is flowing at a veloc
Readme [11.4K]

Answer: Option (d) is the correct answer.

Explanation:

The given data is as follows.

Tube diameter d = 10 mm = 0.01 m

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Density of glycerol (\rho) = 1240 kg/m3

Dynamic viscosity of glycerol (\mu) = 0.0813 pa.s

Reynolds number (Re) = \rho \times velocity \times \frac{density}{\mu}

                                     = 1240 \times 0.5 \times \frac{0.01}{0.0813}

                                     = 76.26

Therefore, according to Reynolds number we can say that flow is laminar.

                     Lt = 0.05 \times Re \times d

                         = 0.05 \times 76.26 \times 0.01

                         = 0.03813 m

As it is known that 1 m = 1000 mm. Hence, in 0.03813 m will be equal to 0.03813 m \times \frac{1000 mm}{1 m}

                         = 38.13 mm

Thus, we can conclude that the transition length of glycerol is 38.13 mm.

5 0
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